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CUET Chemistry Mock Test Alcohol Phenols Ethers AMBIPi

Hi CUET aspirants, Welcome to Amans Maths Blogs (AMBIPi). In this post, you will get CUET Chemistry Mock Alcohol Phenols Ethers AMBIPi. This CUET Chemistry Mock Test is of the Chemistry chapter Alcohol Phenols. Before solving these CUET Chemistry questions, you must read CUET Chemistry Notes, which helps you to revise CUET Chemistry Syllabus and then you must need to solve CUET Previous Years Questions Papers.

CUET Chemistry Mock Test

CUET Chemistry Question No: 1

Which of the following alcohol contains C sp3 − OH bond ?

Option A : Allylic alcohol

Option B : Vinylic alcohol

Option C : Phenols

Option D : None of these

Show/Hide Answer Key

Option A: Allylic alcohol

CUET Exam Chemistry Question No: 2

Vinylic alcohol contains

Option A : —OH group attached to an sp3 -hybridized carbon atom

Option B : —OH group attached to an sp3 -hybridized carbon atom

Option C : —OH group bonded to a carbon-carbon double bond

Option D : —OH group attached to sp3 -hybridised carbon atom next to an aromatic ring

Show/Hide Answer Key

Option C: —OH group bonded to a carbon-carbon double bond

Vinylic alcohols contain — OH group bonded to a carbon-carbon double bond, i.e. to a vinylic carbon or to an aryl carbon. It is as follows

H2C ≡ CH –OH

Vinylic alcohol

CUET UG Chemistry Question No: 3

The IUPAC name of following structure is

Option A : 2-methyl hydroxy cyclopentane.

Option B : 2-hydroxy 2-methyl cyclopentane

Option C : 2-methylcyclopentanol

Option D : cyclopentylmethane

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Option C: 2-methylcyclopentanol

The IUPAC name of the given structure is 2-methyl cyclopentanol. Cyclic alcohols are named using the prefix cyclo and considering the —OH group attached to C-1.

CUET Domain Subject Chemistry Question No: 4

In ethers, the two bond pairs and two lone pairs of electrons on oxygen are arranged in a

Option A : planar arrangement

Option B : tetrahedral arrangement

Option C : trigonal bipyramidal arrangement

Option D : linear arrangement

Show/Hide Answer Key

Option B: tetrahedral arrangement

In ethers, the four electron pairs, i.e. the two bond pairs and two lone pairs of electrons on oxygen are arranged approximately in a tetrahedral arrangement.

CUET BSc Chemistry Question No: 5

The reagent(s) used for the reduction of aldehydes and ketone into alcohols is/are

Option A : finely divided metals such as Pt/Pd/Ni

Option B : sodium borohydride

Option C : lithium aluminium hydride

Option D : All of the above

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Option D: All of the above

Fig. (a) represents structure of triclinic crystal system as, a ≠ b ≠ c and α ≠ β ≠ γ ≠ 90°. Whereas, the structures in option (b), (c) and (d) represents end-centred body centred and face-centred cubic.

CUET Entrance Exam Chemistry Question No: 6

Which of the following reagent is used to reduce carboxylic acids to primary alcohols?

Option A : Pd

Option B : R—OH

Option C : LiAlH4

Option D : Ni

Show/Hide Answer Key

Option C: LiAlH4

CUET Exam Question No: 7

Which of the following hydrocarbon is used for the world wide production of phenol?

Option A : Iso-butylbenzene

Option B : Iso-propylbenzene

Option C : Iso-pentylbenzene

Option D : None of these

Show/Hide Answer Key

Option B: Iso-propylbenzene

CUET Chemistry Practice Questions No: 8

Alcohols and phenols react with active metals to yield

Option A : alkoxides/phenoxides

Option B : hydrogen gas

Option C : nitrogen

Option D : Both (a) and (b)

Show/Hide Answer Key

Option D: Both (a) and (b)

CUET Chemistry Sample Paper Question No: 9

Arrange the following compounds in the decreasing order of acidity.

Option A : H2O>HC≡CH>ROH

Option B : H2O>ROH>HC≡CH

Option C : HC≡CH>ROH>H2O

Option D : HC≡CH>H2O>ROH

Show/Hide Answer Key

Option B: H2O>ROH>HC≡CH

CUET Chemistry Mock Test Question No: 10

Phenols show the cleavage of C— O bond with

Option A : Na

Option B : K

Option C : Zn

Option D : Ca

Show/Hide Answer Key

Option B: crystalline solids

In a cubic close packed lattice of oxide ions, there would be two tetrahedral and one octahedral void per oxide ion.

Since, the formula shows the presence of 4 oxide ions, the number of tetrahedral voids is eight and that of octahedral voids is four. Out of the eight tetrahedral voids, one is occupied by X. ∴ Percentage of tetrahedral voids occupied 1/8 × 100 =12.5 %

CUET Chemistry Question No: 11

Identify an appropriate reagent for the conversion of alcohol to carboxylic acid.

Option A : PCC

Option B : Anhydrous CrO3

Option C : Cu/573 K

Option D : KMnO4/H

Show/Hide Answer Key

Option D: KMnO4/H

CUET Exam Chemistry Question No: 12

Phenol on reaction with conc. HNO3 produces

Option A : o-nitrophenol

Option B : p-nitrophenol

Option C : 2, 4, 6-trinitrophenol

Option D : m-nitrophenol

Show/Hide Answer Key

Option C: 2, 4, 6-trinitrophenol

CUET UG Chemistry Question No: 13

Phenol on reaction with Zn followed by distillation gives‘ ’ X . Which on reaction with CH3COCl, AlCl3 gives Y . Final product Y is

Option A : acetophenone

Option B : benzophenone

Option C : diphenyl

Option D : methyl salicylate

Show/Hide Answer Key

Option A: acetophenone

Packing efficiency for :
Hexagonal close packing (hcp) = 74%
Face-centered cubic close packing (fcc) = 74%
Body centered cubic close packing (bcc) = 68%
and simple cubic (sc) = 52%
Thus, correct order of packing efficiency is :
hcp = fcc > bcc > sc

CUET Domain Subject Chemistry Question No: 14

Which of the following is also known as wood spirit?

Option A : Ethanol

Option B : Propanol

Option C : Methanol

Option D : Butanol

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Option C: Methanol

Methanol, (CH3 OH)  is known as ‘wood spirit’ as it is produced by destructive distillation of wood.

CUET BSc Chemistry Question No: 15

The action of zymase is inhibited during fermentation if the percentage of alcohol formed exceeds

Option A : 5%

Option B : 7%

Option C : 10%

Option D : 14%

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Option D: 14%

CUET Entrance Exam Chemistry Question No: 16

Williamson’s synthesis involves which of the following type of mechanism when attack of an alkoxide ion on primary alkyl halide takes place?

Option A : SN1

Option B : SN2

Option C : E1

Option D : E2

Show/Hide Answer Key

Option B: SN2

Williamson’s synthesis involves S 2 N mechanism when attack of an alkoxide ion on primary alkyl halide takes place. In this mechanism, the incoming nucleophile interacts with alkyl halide causing the carbon halide bond to break while forming a new carbon —OH bond. 

CUET Exam Question No: 17

Among the following sets of reactants which one produces anisole?

Option A : CH3 , CHO , RMgX

Option B : C6H5OH, NaOH, CH3I

Option C : C6H5OH , neutral FeCI3

Option D : C6H5 — CH3 , CH3COCI , AICI3

Show/Hide Answer Key

Option B: C6H5OH, NaOH, CH3I

CUET Chemistry Practice Questions No: 18

Select the correct increasing order of boiling point.

Option A : n-pentane, ethoxyethane, butan-1-ol

Option B : ethoxyethane, n-pentane, butan-1-ol

Option C : butan-1-ol, n-pentane, ethoxyethane

Option D : ethoxyethane, butan-1-ol, n-pentane

Show/Hide Answer Key

Option A: n-pentane, ethoxyethane, butan-1-ol

The weak polarity of ethers do not appreciably affect their boiling points which are comparable to those of the alkanes of comparable molecular masses but are much lower than the boiling point of alcohols. Therefore, the correct increasing order of boiling point is :

n-pentane Ethoxyethane Butan-1-ol Boiling point 309.1 < 307.6 < 390

CUET Chemistry Sample Paper Question No: 19

The order of reactivity of hydrogen halides with ether is as follows :

Option A : HBr > HI > HCl

Option B : HCl > HBr > HI

Option C : HI > HBr > HCl

Option D : HCl > HI > HBr

Show/Hide Answer Key

Option C: HI > HBr > HCl

The order of reactivity of hydrogen halides with ether is as follows. HI > HBr > HCl. The cleavage of ethers take place with concentrated HI or HBr at high temperature.

CUET Chemistry Mock Test Question No: 20

Ethers are treated with an aqueous solution of I in order to remove peroxides from it. Identify the ‘I’ from the following options.

Option A : KI

Option B : Br2

Option C : KCNS

Option D : Na2S2O3

Show/Hide Answer Key

Option A: KI

Ethers are treated with an aqueous solution of KI (I) in order to remove peroxides from it. Ether peroxide oxidises KI into I2 and itself gets reduced to ether. 

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