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CUET Chemistry Sample Papers Organic Compound Containing Nitrogen Amines

Hi CUET aspirants, Welcome to Amans Maths Blogs (AMBIPi). In this post, you will get CUET Chemistry Mock Organic Compound Containing Nitrogen Amines AMBIPi. This CUET Chemistry Mock Test is of the Chemistry chapter Organic Compound Containing Nitrogen Amines. Before solving these CUET Chemistry questions, you must read CUET Chemistry Notes, which helps you to revise CUET Chemistry Syllabus and then you must need to solve CUET Previous Years Questions Papers.

CUET Chemistry Mock Test

CUET Chemistry Question No: 1

The hybridization and geometry of amines are sp3 and pyramidal respectively due to the presence of Carbonyl compounds are the constituents of

Option A : divalent N-atom

Option B : trivalent N-atom

Option C : monovalent N-atom

Option D : tetravalent N-atom

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Option B: trivalent N-atom

Due to the presence of trivalent N-atom and unshared pair of electrons in amines, hybridization and geometry become sp3 and pyramidal respectively.

CUET Exam Chemistry Question No: 2

What is the bond angle of C — N—E (E = C or H) in case of trimethylamine?

Option A : 109.5°

Option B : More than 109.5°

Option C : 108°

Option D : 90°

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Option C: 108°

The C—N—E angle is 108° in case of trimethylamine due to the presence of unshared pair of electrons in it.

CUET UG Chemistry Question No: 3

If one H-atom of ammonia is replaced by alkyl group, the amine, thus obtained is known as

Option A : secondary amine

Option B : primary amine

Option C : tertiary amine

Option D : quaternary amine

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Option B: primary amine

CUET Domain Subject Chemistry Question No: 4

Which of the following is an aromatic amine?

Option A : Aniline

Option B : N-methyl aniline

Option C : 2-phenyl ethanamine

Option D : None of the above

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Option A: Aniline

Aromatic amine is aniline and its IUPAC name is benzamine.

CUET BSc Chemistry Question No: 5

What is the correct order of reactivity of halides with amines?

Option A : RC I> RBr > RI

Option B : RI >RBr > RCI

Option C : RCI >RI > RBr

Option D : RI >RCI > RBr

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Option B: RI >RBr > RCI

CUET Entrance Exam Chemistry Question No: 6

Which of the following can be prepared using Gabriel phthalimide synthesis?

Option A : Primary aromatic amines

Option B : Secondary amines

Option C : Primary aliphatic amines

Option D : Tertiary amines

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Option C: Primary aliphatic amines

Primary aliphatic amines can be prepared by Gabriel phthalimide synthesis. Secondary and tertiary amines cannot be prepared by this method due to steric hindrance. Aromatic primary amines cannot be prepared because aryl halides do not undergo nucleophilic substitution with the anion formed by phthalimide.

CUET Exam Question No: 7

Which of the following reactions is appropriate for converting acetamide to methanamine?

Option A : Carbylamine reaction

Option B : Hofmann bromamide reaction

Option C : Stephen’s reaction

Option D : Gabriel’s phthalimide synthesis

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Option B: Hofmann bromamide reaction 

The conversion of acetamide to methanamine can be achieved by Hofmann bromamide reaction. It involves the migration of alkyl or aryl with its electron pair to electron deficient N from adjacent carbon. The reaction involves the intermediate isocyanate.

CUET Chemistry Practice Questions No: 8

Which of the following can form H-bond?

Option A : NH3

Option B : R — CH3

Option C : R — O — R

Option D : R — Br

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Option A: NH3

The attractive electrostatic force between a hydrogen atom and an electronegative atom (F, O, N) is known as hydrogen bond.

CUET Chemistry Sample Paper Question No: 9

Amines behave as a nucleophile because of

Option A : the presence of unshared pair of electrons on N-atom

Option B : the absence of unshared pair of electrons on N-atom

Option C : the vacant p-orbital of N-atom

Option D : All of the above

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Option B: the absence of unshared pair of electrons on N-atom

CUET Chemistry Mock Test Question No: 10

Amines on treatment with acids yield salt because they are

Option A : basic in nature

Option B : acidic in nature

Option C : amphoteric in nature

Option D : None of these

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Option A: basic in nature

CUET Chemistry Question No: 11

Aniline is more stable than anilinium ion because

Option A : it has more resonating structures.

Option B : has less resonating structures.

Option C : it has more π-bonding.

Option D : it has less π-bonding

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Option A: it has more resonating structures 

Aniline is a resonance hybrid of five resonating structures and anilinium ion is obtained when aniline accept a proton and has only two resonating structures. Greater the number of resonating structures, greater is the stability. Therefore, aniline is more stable than anilinium ion.

CUET Exam Chemistry Question No: 12

The carbylamine reaction is given by

Option A : (C2H5)3N

Option B : (C2H5)2 NH

Option C : C2 H5NH2

Option D : C3H7NHC2H5

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Option C: C2 H5NH2

CUET UG Chemistry Question No: 13

Name the product(s) formed during the reaction of primary aliphatic amines with nitrous acid at room temperature?

Option A : RNO2

Option B : ROH

Option C : Both (a) and (b)

Option D : None of these

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Option B: ROH

Primary aliphatic amines react with nitrous acid to form aliphatic diazonium salts which being unstable, form alcohol and liberate nitrogen gas quantitatively .So, the product formed is R — OH

CUET Domain Subject Chemistry Question No: 14

The chemical formula of Hinsberg’s reagent is

Option A : HNO2

Option B : NaOH + CaO

Option C : C6H5SO2CI

Option D : CH3CONO2

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Option C: C6H5SO2CI

The chemical formula of Hinsberg’s reagent is  C6H5SO2 i.e. benzene sulphonyl chloride.

CUET BSc Chemistry Question No: 15

—NH2 group in aniline is activating group and, hence reaction occurs at

Option A : para position

Option B : ortho position

Option C : meta position

Option D : Both (a) and (b)

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Option D: Both (a) and (b)

CUET Entrance Exam Chemistry Question No: 16

Aniline does not undergo Friedel-Crafts reaction due to

Option A : less reactivity of aniline

Option B : salt formation with AICI3

Option C : electron accepting effect of – NH2 group present in aniline

Option D : None of the above

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Option B: salt formation with AICI3

Aniline does not undergo Friedel-Craft’s reaction  (alkylation and acetylation) due to salt formation with AICI3 the Lewis acid, which is used as a catalyst. Due to this, nitrogen of aniline acquires positive charge and, hence acts as a strong deactivating group.

CUET Exam Question No: 17

Which of the following amine will form stable diazonium salt at 273-278 K?

Option A : C2H5NH2

Option B : C6H5NH2

Option C : C6H5CH2NH2

Option D : C6H5N(CH3)2

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Option B: C6H5NH2

Primary aromatic amines (C6H5NH2) form arene diazonium salts which are stable for a short time in solution at low temperatures (273-278 K).

CUET Chemistry Practice Questions No: 18

Which of the following compound is water insoluble and stable at room temperature?

Option A : Benzene diazonium chloride

Option B : Benzene diazonium fluoroborate

Option C : Both (a) and (b)

Option D : None of the above

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Option B: Benzene diazonium fluoroborate 

Benzene diazonium fluoroborate is water insoluble and stable at room temperature, whereas benzene diazonium chloride is soluble in water and is stable in cold but reacts with water, when warmed.

CUET Chemistry Sample Paper Question No: 19

The reagent used to form aryl fluoride from arene diazonium chloride is

Option A : HF

Option B : KF

Option C : HBF4

Option D : None of these

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Option C: HBF4

The order of reactivity of hydrogen halides with ether is as follows. HI > HBr > HCl. The cleavage of ethers take place with concentrated HI or HBr at high temperature.

CUET Chemistry Mock Test Question No: 20

Coupling reaction is an example of

Option A : nucleophilic addition reaction.

Option B : nucleophilic substitution reaction.

Option C : electrophilic substitution reaction.

Option D : electrophilic addition reaction.

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Option C: electrophilic substitution reaction.

Coupling reaction is an example of electrophilic substitution reaction. In this reaction, benzene diazonium chloride reacts with phenol/aniline in which the phenol/aniline molecule at its para position is coupled with the diazonium salt to form p-hydroxy azobenzene/ p-amino azobenzene.

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