Hi students, Welcome to **Amans Maths Blogs (AMBIPi)**. Are you preparing for **SSC CGL Tier 1 and 2** and looking for * SSC CGL Exam Math Number System Paper with Solutions AMBIPi*? In this article, you will get Previous Year Mathematics Questions asked in SSC CGL Tier 1 and Tier 2, which helps you in the preparation of government job exams of SSC CGL.

### SSC CGL Exam Math Number System Question with Solutions

**SSC CGL Exam Math Question: 1**

A number divided by 13 leaves a remainder 1 and if the quotient, thus obtained, is divided by 5,we get a remainder of 3. What will be the remainder if the number is divided by 65 ?

**Option A** : 28

**Option B** : 16

**Option C** : 18

**Option D** : 40

**Show/Hide Answer Key**

**Option D : 40**

y = 5 × 1 + 3 = 8

x = 13 × 8 + 1 = 105

On dividing 105 by 65, remain-der = 40

**SSC CGL Previous Year Math Questions: 2**

Which of the following number is NOT divisible by 18 ?

**Option A** : 54036

**Option B** : 50436

**Option C** : 34056

**Option D** : 65043

**Show/Hide Answer Key**

**Option D : 65043**

A number will be exactly di-visible by 18 if it is divisible by 2 and 9 both. Clearly 65043 is not divisible by 2.

Required number = 65043

**SSC CGL Previous Year Math Paper: 3**

64329 is divided by a certain number. While dividing, the numbers, 175, 114 and 213 appear as three successive remainders. The divisor is

**Option A** : 184

**Option B** : 224

**Option C** : 234

**Option D** : 296

**Show/Hide Answer Key**

**Option C : 234**

Number at (i) = 643 – 175 = 468

Number at (ii) = 1752 – 114 = 1638

Number at (iii) = 1149 – 213 = 936

Clearly, 468, 1638 and 936 are

multiples of 234 and 234 > 213.

Divisor = 234

**SSC CGL Mock Test Math Question: 4**

In a question on division, the di-visor is 7 times the quotient and3 times the remainder. If the remainder is 28, then the dividend is Which of the following fraction is the smallest?

**Option A** : 588

**Option B** : 784

**Option C** : 823

**Option D** : 1036

**Show/Hide Answer Key**

**Option D : 1036**

Let the quotient be Q and the remainder be R. Then

Divisor = 7 Q = 3 R \ Q = 3/7

R =3/7× 28 = 12\ Divisor = 7 Q = 7 × 12 = 84\ Dividend = Divisor × Quotient+ Remainder = 84 × 12 + 28 =

1008 + 28 = 1036

**SSC CGL Free Mock Test Math Question: 5**

If two numbers are each divided by the same divisor, the remainders are respectively 3 and 4. If the sum of the two numbers be divided by the same divisor, the remainder is 2. The divisor is

**Option A** : 9

**Option B** : 7

**Option C** : 5

**Option D** : 3

**Show/Hide Answer Key**

**Option C : 5**

Required divisor = 3 + 4 – 2 = 5

**SSC CGL Advance Math Question: 6**

A number consists of two digits. If the number formed by inter- changing the digits is added to the original number, the result-ing number (i.e. the sum) must be divisible by

**Option A** : 11

**Option B** : 9

**Option C** : 5

**Option D** : 3

**Show/Hide Answer Key**

**Option A :**11

Let the number be 10x + y After interchanging the digits,

the number obtained = 10y + x According to the question,

Resulting number = 10x + y + 10y + x = 11x + 11y = 11 (x + y) which is exactly di-visible by 11.

**SSC CGL Math Previous Year Question: 7**

A number when divided by 5 leaves a remainder 3. What is the remainder when the square of the same number is divided by 5 ?

**Option A** : 1

**Option B** : 2

**Option C** : 3

**Option D** : 4

**Show/Hide Answer Key**

**Option D : 4**

**SSC CGL Math Question Paper: 8**

A number when divided by 192 gives a remainder of 54. What remainder would be obtained on dividing the same number by 16 ?

**Option A** : 2

**Option B** : 4

**Option C** : 6

**Option D** : 8

**Show/Hide Answer Key**

**Option C : 6**

Here, the first divisor 192 is a multiple of second divisor 16. Required remainder = remainder obtained by divid- ing 54 by 16 = 6

**Advance Math Question Asked in SSC CGL: 9**

A number, when divided by 136, leaves remainder 36. If the same number is divided by 17, the re-mainder will be

**Option A** : 9

**Option B** : 7

**Option C** : 3

**Option D** : 2

**Show/Hide Answer Key**

**Option D : 2**

If the first divisor be a multiple of the second divisor, then required remainder = remainder obtained by dividing the first remainder (36) by the second divisor (17) = 2

**Previous Year Math Question Paper SSC CGL: 10**

Two numbers, when divided by 17, leave remainders 13 and 11 respectively. If the sum of those two numbers is divided by 17, the remainder will be

**Option A** : 13

**Option B** : 11

**Option C** : 7

**Option D** : 4

**Show/Hide Answer Key**

**Option C :**7

Required remainder = Remainder obtained on dividing 11 + 13 i.e. 24 by 17 = 7

**SSC CGL Exam Math Number System Question: 11**

A number, when divided by 221, leaves a remainder 64. What is the remainder if the same num-ber is divided by 13 ?

**Option A** : 0

**Option B** : 1

**Option C** : 11

**Option D** : 12

**Show/Hide Answer Key**

**Option D :12**

Here, the first divisor (221) is a multiple of second divisor (13) Hence, required remainder = remainder obtained on dividing 64 by 13 = 12

**SSC CGL Previous Year Math Number System Questions: 12**

When ‘n’ is divisible by 5 the remainder is 2. What is the remain-der when n 2 is divided by 5 ?

**Option A** : 2

**Option B** : 3

**Option C** : 1

**Option D** : 4

**Show/Hide Answer Key**

**Option D : 4**

Required remainder = Remainder obtained by dividing 22 by 5.

Remainder = 4

**SSC CGL Previous Year Math Number System Paper: 13**

The remainder when 321 is divided by 5 is

**Option A** : 1

**Option B** : 2

**Option C** : 3

**Option D** : 4

**Show/Hide Answer Key**

**Option C : 3**

**SSC CGL Mock Test Math Number System Question: 14**

A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as

**Option A** : 4

**Option B** : 3

**Option C** : 2

**Option D** : 5

**Show/Hide Answer Key**

**Option A : 4**

Here, the first divisor i.e. 49 is multiple of second divisor i.e. 7.

Required remainder = Remainder obtained on dividing 32 by 7 = 4

**SSC CGL Free Mock Test Math Number System Question: 15**

When a number is divided by 36, the remainder is 19. What will be the remainder when the number is divided by 12 ?

**Option A** : 7

**Option B** : 5

**Option C** : 3

**Option D** : 0

**Show/Hide Answer Key**

**Option D : 7**

Here, the first divisor (36) is exactly divisible by the second divisor (12).

Required remainder = Remainder obtained after 19 is divided by 12 = 7

**SSC CGL Advance Math Number System Question: 16**

9^{6} – 11 when divided by 8 would leave a remainder of :

**Option A** : 0

**Option B** : 1

**Option C** : 2

**Option D** : 3

**Show/Hide Answer Key**

**Option D : 3**

**SSC CGL Math Previous Year Number System Question: 17**

If 17^{200} is divided by 18, the remainder is—

**Option A** : 17

**Option B** : 16

**Option C** : 1

**Option D** : 2

**Show/Hide Answer Key**

**Option C : 1**

**SSC CGL Math Number System Question Paper: 18**

When 2^{31} is divided by 5 the remainder is

**Option A** : 4

**Option B** : 3

**Option C** : 2

**Option D** : 1

**Show/Hide Answer Key**

**Option B : 3**

Clearly, the remainder will be 3 when divided by 5.

Illustration :

23 ÷ 5 gives remainder = 3

83 ÷ 5 gives remainder = 3

**Advance Math Number System Question Asked in SSC CGL: 19**

A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first add- ed 12 to the number and then di-vided it by 6, getting 112 as the answer. The correct answer should have been

**Option A** : 124

**Option B** : 122

**Option C** : 118

**Option D** : 114

**Show/Hide Answer Key**

**Option B : 122**

Correct answer = 660/6+12 = 110 + 12 = 122

**Previous Year Math Number System Question Paper SSC CGL: 20**

The greatest common divisor of 3^{3333} + 1 and 3^{3334} + 1 is

**Option A** : 2

**Option B** : 1

**Option C** : 3^{3333} + 1

**Option D** : 20

**Show/Hide Answer Key**

**Option D : 4 **

3^{1}= 3, 3^{2} = 9,

3^{3} = 27, 3^{4} = 81

i.e. the unit’s digit = odd number Hence, both numbers are divisible by 2.