Monday, May 20, 2024
Home > Latest Announcement > SSC CGL Previous Year Math Number System Paper with Solutions

# SSC CGL Previous Year Math Number System Paper with Solutions

Hi students, Welcome to Amans Maths Blogs (AMBIPi). Are you preparing for SSC CGL Tier 1 and 2 and looking for SSC CGL Exam Math Number System Paper with Solutions AMBIPi? In this article, you will get Previous Year Mathematics Questions asked in SSC CGL Tier 1 and Tier 2, which helps you in the preparation of government job exams of SSC CGL.

### SSC CGL Exam Math Number System Question with Solutions

SSC CGL Exam Math Question: 1

A number divided by 13 leaves a remainder 1 and if the quotient, thus obtained, is divided by 5,we get a remainder of 3. What will be the remainder if the number is divided by 65 ?

Option A : 28

Option B : 16

Option C : 18

Option D : 40

Option D : 40

y = 5 × 1 + 3 = 8

x = 13 × 8 + 1 = 105

On dividing 105 by 65, remain-der = 40

SSC CGL Previous Year Math Questions: 2

Which of the following number is NOT divisible by 18 ?

Option A : 54036

Option B : 50436

Option C : 34056

Option D : 65043

Option D : 65043

A number will be exactly di-visible by 18 if it is divisible by 2 and 9 both. Clearly 65043 is not divisible by 2.
Required number = 65043

SSC CGL Previous Year Math Paper: 3

64329 is divided by a certain number. While dividing, the numbers, 175, 114 and 213 appear as three successive remainders. The divisor is

Option A : 184

Option B : 224

Option C : 234

Option D : 296

Option C : 234

Number at (i) = 643 – 175 = 468

Number at (ii) = 1752 – 114 = 1638
Number at (iii) = 1149 – 213 = 936
Clearly, 468, 1638 and 936 are
multiples of 234 and 234 > 213.
Divisor = 234

SSC CGL Mock Test Math Question: 4

In a question on division, the di-visor is 7 times the quotient and3 times the remainder. If the remainder is 28, then the dividend is Which of the following fraction is the smallest?

Option A : 588

Option B : 784

Option C : 823

Option D : 1036

Option D : 1036

Let the quotient be Q and the remainder be R. Then

Divisor = 7 Q = 3 R \ Q = 3/7
R =3/7× 28 = 12\ Divisor = 7 Q = 7 × 12 = 84\ Dividend = Divisor × Quotient+ Remainder = 84 × 12 + 28 =
1008 + 28 = 1036

SSC CGL Free Mock Test Math Question: 5

If two numbers are each divided by the same divisor, the remainders are respectively 3 and 4. If the sum of the two numbers be divided by the same divisor, the remainder is 2. The divisor is

Option A : 9

Option B : 7

Option C : 5

Option D : 3

Option C : 5

Required divisor = 3 + 4 – 2 = 5

SSC CGL Advance Math Question: 6

A number consists of two digits. If the number formed by inter- changing the digits is added to the original number, the result-ing number (i.e. the sum) must be divisible by

Option A : 11

Option B : 9

Option C : 5

Option D : 3

Option A :11

Let the number be 10x + y After interchanging the digits,

the number obtained = 10y + x According to the question,

Resulting number = 10x + y + 10y + x = 11x + 11y = 11 (x + y) which is exactly di-visible by 11.

SSC CGL Math Previous Year Question: 7

A number when divided by 5 leaves a remainder 3. What is the remainder when the square of the same number is divided by 5 ?

Option A : 1

Option B : 2

Option C : 3

Option D : 4

Option D : 4

SSC CGL Math Question Paper: 8

A number when divided by 192 gives a remainder of 54. What remainder would be obtained on dividing the same number by 16 ?

Option A : 2

Option B : 4

Option C : 6

Option D : 8

Option C : 6

Here, the first divisor 192 is a multiple of second divisor 16. Required remainder = remainder obtained by divid- ing 54 by 16 = 6

A number, when divided by 136, leaves remainder 36. If the same number is divided by 17, the re-mainder will be

Option A : 9

Option B : 7

Option C : 3

Option D : 2

Option D : 2

If the first divisor be a multiple of the second divisor, then required remainder = remainder obtained by dividing the first remainder (36) by the second divisor (17) = 2

Previous Year Math Question Paper SSC CGL: 10

Two numbers, when divided by 17, leave remainders 13 and 11 respectively. If the sum of those two numbers is divided by 17, the remainder will be

Option A : 13

Option B : 11

Option C : 7

Option D : 4

Option C :7

Required remainder = Remainder obtained on dividing 11 + 13 i.e. 24 by 17 = 7

SSC CGL Exam Math Number System Question: 11

A number, when divided by 221, leaves a remainder 64. What is the remainder if the same num-ber is divided by 13 ?

Option A : 0

Option B : 1

Option C : 11

Option D : 12

Option D :12

Here, the first divisor (221) is a multiple of second divisor (13) Hence, required remainder = remainder obtained on dividing 64 by 13 = 12

SSC CGL Previous Year Math Number System Questions: 12

When ‘n’ is divisible by 5 the remainder is 2. What is the remain-der when n 2 is divided by 5 ?

Option A : 2

Option B : 3

Option C : 1

Option D : 4

Option D : 4

Required remainder = Remainder obtained by dividing 22 by 5.
Remainder = 4

SSC CGL Previous Year Math Number System Paper: 13

The remainder when 321 is divided by 5 is

Option A : 1

Option B : 2

Option C : 3

Option D : 4

Option C : 3

SSC CGL Mock Test Math Number System Question: 14

A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as

Option A : 4

Option B : 3

Option C : 2

Option D : 5

Option A : 4

Here, the first divisor i.e. 49 is multiple of second divisor i.e. 7.
Required remainder = Remainder obtained on dividing 32 by 7 = 4

SSC CGL Free Mock Test Math Number System Question: 15

When a number is divided by 36, the remainder is 19. What will be the remainder when the number is divided by 12 ?

Option A : 7

Option B : 5

Option C : 3

Option D : 0

Option D : 7

Here, the first divisor (36) is exactly divisible by the second divisor (12).
Required remainder = Remainder obtained after 19 is divided by 12 = 7

SSC CGL Advance Math Number System Question: 16

96 – 11 when divided by 8 would leave a remainder of :

Option A : 0

Option B : 1

Option C : 2

Option D : 3

Option D : 3

SSC CGL Math Previous Year Number System Question: 17

If 17200 is divided by 18, the remainder is—

Option A : 17

Option B : 16

Option C : 1

Option D : 2

Option C : 1

SSC CGL Math Number System Question Paper: 18

When 231 is divided by 5 the remainder is

Option A : 4

Option B : 3

Option C : 2

Option D : 1

Option B : 3

Clearly, the remainder will be 3 when divided by 5.
Illustration :
23 ÷ 5 gives remainder = 3
83 ÷ 5 gives remainder = 3

A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first add- ed 12 to the number and then di-vided it by 6, getting 112 as the answer. The correct answer should have been

Option A : 124

Option B : 122

Option C : 118

Option D : 114

Option B : 122

Correct answer = 660/6+12 = 110 + 12 = 122

Previous Year Math Number System Question Paper SSC CGL: 20

The greatest common divisor of 33333 + 1 and 33334 + 1 is

Option A : 2

Option B : 1

Option C : 33333 + 1

Option D : 20