Hi students, Welcome to Amans Maths Blogs (AMBIPi). Are you preparing for SSC CGL Tier 1 and 2 and looking for SSC CGL Exam Math Number System Paper with Solutions AMBIPi? In this article, you will get Previous Year Mathematics Questions asked in SSC CGL Tier 1 and Tier 2, which helps you in the preparation of government job exams of SSC CGL.
SSC CGL Exam Math Number System Question with Solutions
SSC CGL Exam Math Question: 1
A number divided by 13 leaves a remainder 1 and if the quotient, thus obtained, is divided by 5,we get a remainder of 3. What will be the remainder if the number is divided by 65 ?
Option A : 28
Option B : 16
Option C : 18
Option D : 40
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Option D : 40
y = 5 × 1 + 3 = 8
x = 13 × 8 + 1 = 105
On dividing 105 by 65, remain-der = 40
SSC CGL Previous Year Math Questions: 2
Which of the following number is NOT divisible by 18 ?
Option A : 54036
Option B : 50436
Option C : 34056
Option D : 65043
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Option D : 65043
A number will be exactly di-visible by 18 if it is divisible by 2 and 9 both. Clearly 65043 is not divisible by 2.
Required number = 65043
SSC CGL Previous Year Math Paper: 3
64329 is divided by a certain number. While dividing, the numbers, 175, 114 and 213 appear as three successive remainders. The divisor is
Option A : 184
Option B : 224
Option C : 234
Option D : 296
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Option C : 234
Number at (i) = 643 – 175 = 468
Number at (ii) = 1752 – 114 = 1638
Number at (iii) = 1149 – 213 = 936
Clearly, 468, 1638 and 936 are
multiples of 234 and 234 > 213.
Divisor = 234
SSC CGL Mock Test Math Question: 4
In a question on division, the di-visor is 7 times the quotient and3 times the remainder. If the remainder is 28, then the dividend is Which of the following fraction is the smallest?
Option A : 588
Option B : 784
Option C : 823
Option D : 1036
Show/Hide Answer Key
Option D : 1036
Let the quotient be Q and the remainder be R. Then
Divisor = 7 Q = 3 R \ Q = 3/7
R =3/7× 28 = 12\ Divisor = 7 Q = 7 × 12 = 84\ Dividend = Divisor × Quotient+ Remainder = 84 × 12 + 28 =
1008 + 28 = 1036
SSC CGL Free Mock Test Math Question: 5
If two numbers are each divided by the same divisor, the remainders are respectively 3 and 4. If the sum of the two numbers be divided by the same divisor, the remainder is 2. The divisor is
Option A : 9
Option B : 7
Option C : 5
Option D : 3
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Option C : 5
Required divisor = 3 + 4 – 2 = 5
SSC CGL Advance Math Question: 6
A number consists of two digits. If the number formed by inter- changing the digits is added to the original number, the result-ing number (i.e. the sum) must be divisible by
Option A : 11
Option B : 9
Option C : 5
Option D : 3
Show/Hide Answer Key
Option A :11
Let the number be 10x + y After interchanging the digits,
the number obtained = 10y + x According to the question,
Resulting number = 10x + y + 10y + x = 11x + 11y = 11 (x + y) which is exactly di-visible by 11.
SSC CGL Math Previous Year Question: 7
A number when divided by 5 leaves a remainder 3. What is the remainder when the square of the same number is divided by 5 ?
Option A : 1
Option B : 2
Option C : 3
Option D : 4
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Option D : 4
SSC CGL Math Question Paper: 8
A number when divided by 192 gives a remainder of 54. What remainder would be obtained on dividing the same number by 16 ?
Option A : 2
Option B : 4
Option C : 6
Option D : 8
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Option C : 6
Here, the first divisor 192 is a multiple of second divisor 16. Required remainder = remainder obtained by divid- ing 54 by 16 = 6
Advance Math Question Asked in SSC CGL: 9
A number, when divided by 136, leaves remainder 36. If the same number is divided by 17, the re-mainder will be
Option A : 9
Option B : 7
Option C : 3
Option D : 2
Show/Hide Answer Key
Option D : 2
If the first divisor be a multiple of the second divisor, then required remainder = remainder obtained by dividing the first remainder (36) by the second divisor (17) = 2
Previous Year Math Question Paper SSC CGL: 10
Two numbers, when divided by 17, leave remainders 13 and 11 respectively. If the sum of those two numbers is divided by 17, the remainder will be
Option A : 13
Option B : 11
Option C : 7
Option D : 4
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Option C :7
Required remainder = Remainder obtained on dividing 11 + 13 i.e. 24 by 17 = 7
SSC CGL Exam Math Number System Question: 11
A number, when divided by 221, leaves a remainder 64. What is the remainder if the same num-ber is divided by 13 ?
Option A : 0
Option B : 1
Option C : 11
Option D : 12
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Option D :12
Here, the first divisor (221) is a multiple of second divisor (13) Hence, required remainder = remainder obtained on dividing 64 by 13 = 12
SSC CGL Previous Year Math Number System Questions: 12
When ‘n’ is divisible by 5 the remainder is 2. What is the remain-der when n 2 is divided by 5 ?
Option A : 2
Option B : 3
Option C : 1
Option D : 4
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Option D : 4
Required remainder = Remainder obtained by dividing 22 by 5.
Remainder = 4
SSC CGL Previous Year Math Number System Paper: 13
The remainder when 321 is divided by 5 is
Option A : 1
Option B : 2
Option C : 3
Option D : 4
Show/Hide Answer Key
Option C : 3
SSC CGL Mock Test Math Number System Question: 14
A number when divided by 49 leaves 32 as remainder. This number when divided by 7 will have the remainder as
Option A : 4
Option B : 3
Option C : 2
Option D : 5
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Option A : 4
Here, the first divisor i.e. 49 is multiple of second divisor i.e. 7.
Required remainder = Remainder obtained on dividing 32 by 7 = 4
SSC CGL Free Mock Test Math Number System Question: 15
When a number is divided by 36, the remainder is 19. What will be the remainder when the number is divided by 12 ?
Option A : 7
Option B : 5
Option C : 3
Option D : 0
Show/Hide Answer Key
Option D : 7
Here, the first divisor (36) is exactly divisible by the second divisor (12).
Required remainder = Remainder obtained after 19 is divided by 12 = 7
SSC CGL Advance Math Number System Question: 16
96 – 11 when divided by 8 would leave a remainder of :
Option A : 0
Option B : 1
Option C : 2
Option D : 3
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Option D : 3
SSC CGL Math Previous Year Number System Question: 17
If 17200 is divided by 18, the remainder is—
Option A : 17
Option B : 16
Option C : 1
Option D : 2
Show/Hide Answer Key
Option C : 1
SSC CGL Math Number System Question Paper: 18
When 231 is divided by 5 the remainder is
Option A : 4
Option B : 3
Option C : 2
Option D : 1
Show/Hide Answer Key
Option B : 3
Clearly, the remainder will be 3 when divided by 5.
Illustration :
23 ÷ 5 gives remainder = 3
83 ÷ 5 gives remainder = 3
Advance Math Number System Question Asked in SSC CGL: 19
A student was asked to divide a number by 6 and add 12 to the quotient. He, however, first add- ed 12 to the number and then di-vided it by 6, getting 112 as the answer. The correct answer should have been
Option A : 124
Option B : 122
Option C : 118
Option D : 114
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Option B : 122
Correct answer = 660/6+12 = 110 + 12 = 122
Previous Year Math Number System Question Paper SSC CGL: 20
The greatest common divisor of 33333 + 1 and 33334 + 1 is
Option A : 2
Option B : 1
Option C : 33333 + 1
Option D : 20
Show/Hide Answer Key
Option D : 4
31= 3, 32 = 9,
33 = 27, 34 = 81
i.e. the unit’s digit = odd number Hence, both numbers are divisible by 2.
