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# NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5

Hi Students, Welcome to Amans Maths Blogs (AMB). In this post, you will get the NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5.

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NCERT Solutions for class 12 is highly recommended by the experienced teacher for students who are going to appear in CBSE Class 12 and JEE Mains and Advanced and NEET level exams. Here You will get NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5 of all questions given in NCERT textbooks of class 12 in details with step by step process.

NCERT Solutions for Class 12 Maths are not only the solutions of Maths exercise but it builds your foundation of other important subjects. Getting knowledge of depth concept of CBSE Class 12th Maths like Algebra, Calculus, Trigonometry, Coordinate Geometry help you to understand the concept of Physics and Physical Chemistry.

## NCERT Solutions for Class 12 Maths Differential Equations

In each of the Exercises 1 to 10, show that the given differential equation is homogeneous and solve each of them.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 1.

(x2 + xy) dy = (x2 + y2) dx

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 2.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 3.

(x – y) dy – (x + y) dx = 0

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 4.

(x2 – y2) dx + 2xy dy = 0

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 5.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 6.

NCERT Solutions:

Given differential equation is

or

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 7.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

Integrating, we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 8.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

Integrating, we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 9.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get

On substituting y = vx and in equation (1), we get

Integrating, we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 10.

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dx/dy is in form of g(x/y), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put x = vy                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting x = vy and  in equation (1), we get

Integrating, we get

where C is an arbitrary constant. This is required general solution of the given differential equation.

For each of the differential equations in Exercises from 11 to 15, find the particular solution satisfying the given condition:

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 11.

(x + y) dy + (x – y) dx = 0; y = 1 when x = 1

NCERT Solutions:

Given differential equation is (x + y) dy + (x – y) dx = 0.

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting y = vx and  in equation (1), we get

Integrating, we get

…(3)

where C is an arbitrary constant. This is required general solution of the given differential equation.

It is given that y = 1 when x = 1.

From the equation (3), we get

Substituting the value of C in equation (3), we get

This is required particular solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 12.

x2 dy + (xy + y2) dx = 0; y = 1 when x = 1

NCERT Solutions:

Given differential equation is x2 dy + (xy + y2) dx = 0.

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting y = vx and  in equation (1), we get

Integrating, we get

…(3)

where C is an arbitrary constant. This is general solution of the given differential equation.

It is given that y = 1 when x = 1.

From the equation (3), we get

Substituting the value of C in equation (3), we get

This is required particular solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 13.

y = π/4 when x = 1

NCERT Solutions:

Given differential equation is

…(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting y = vx and  in equation (1), we get

Integrating, we get

…(3)

where C is an arbitrary constant. This is general solution of the given differential equation.

It is given that y = π/4 when x = 1.

From the equation (3), we get

Substituting the value of C in equation (3), we get

This is required particular solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 14.

y = 0 when x = 1

NCERT Solutions:

Given differential equation is

…(1)

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting y = vx and  in equation (1), we get

Integrating, we get

…(3)

where C is an arbitrary constant. This is general solution of the given differential equation.

It is given that y = 0 when x = 1.

From the equation (3), we get

Substituting the value of C in equation (3), we get

This is required particular solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 15.

y = 2 when x = 1

NCERT Solutions:

Given differential equation is

…(1)

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to y, we get

On substituting y = vx and  in equation (1), we get

Integrating, we get

…(3)

where C is an arbitrary constant. This is general solution of the given differential equation.

It is given that y = 2 when x = 1.

From the equation (3), we get

Substituting the value of C in equation (3), we get

This is required particular solution of the given differential equation.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 16.

A homogeneous differential equation of the from  can be solved by making the substitution.

(A) y = vx

(B) v = yx

(C) x = vy

(D) x = v

NCERT Solutions:

To solve the homogeneous differential equation of the from  , we need to put x = vy.

NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.5: Ques No 17.

Which of the following is a homogeneous differential equation?

(A) (4x + 6y + 5) dy – (3y + 2x + 4) dx = 0

(B) (xy) dx – (x3 + y3) dy = 0

(C) (x3 + 2y2) dx + 2xy dy = 0

(D) y2 dx + (x2 – xy – y2) dy = 0

NCERT Solutions:

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