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# NCERT Solutions for Class 12 Maths Differential Equations Miscellaneous Exercise

Hi Students, Welcome to Amans Maths Blogs (AMB). In this post, you will get the NCERT Solutions for Class 12 Maths Differential Equations Miscellaneous Exercise.

CBSE Class 12th is an important school class in your life as you take some serious decision about your career. And out of all subjects, Maths is an important and core subjects. So CBSE NCERT Solutions for Class 12th Maths is major role in your exam preparation as it has detailed chapter wise solutions for all exercise. This NCERT Solutions can be downloaded in PDF file. The downloading link is given at last.

NCERT Solutions for class 12 is highly recommended by the experienced teacher for students who are going to appear in CBSE Class 12 and JEE Mains and Advanced and NEET level exams. Here You will get NCERT Solutions for Class 12 Maths Differential Equations Miscellaneous Exercise of all questions given in NCERT textbooks of class 12 in details with step by step process.

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## NCERT Solutions for Class 12 Maths Differential Equations Miscellaneous Exercise

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 1

For each of the differential equations given below, indicate its order and degree (if defined).

(i) NCERT Solutions:

Given differential equation is The highest order derivative present in the given differential equation is , so its order is TWO.

The given differential equation is a polynomial equation in its derivatives and the highest power of the derivative is one. So, its degree is ONE.

(ii) NCERT Solutions:

Given differential equation is The highest order derivative present in the given differential equation is , so its order is ONE.

The given differential equation is a polynomial equation in its derivatives and the highest power of the derivative is three. So, its degree is THREE.

(iii) NCERT Solutions:

Given differential equation is .

The highest order derivative present in the given differential equation is , so its order is FOUR.

The given differential equation is not a polynomial equation in its derivatives and so its degree is NOT Defined.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 2

For each of the exercises given below, verify that the given function (implicit or explicit) is a solution of the corresponding differential equation.

(i) Check whether the function y = aex + be–x + x2 is the solution of .

NCERT Solutions:

Given function is y = aex + be–x + x2       …(1)

Differentiating the equation (1) with respect to x, we get …(2)

Differentiating the equation (2) with respect to x, we get …(3)

Now, Thus, the given function y = aex + be–x + x2 is NOT the solution of .

(ii) Check whether the function y = ex (a cos x + b sin x) is the solution of .

NCERT Solutions:

Given function is y = ex(a cos x + b sin x)       …(1)

Differentiating the equation (1) with respect to x, we get  …(2)

Differentiating the equation (2) with respect to x, we get  …(3)

Now, Thus, the given function y = ex (a cos x + b sin x) is the solution of .

(iii) Check whether the function y = x sin 3x is the solution of .

NCERT Solutions:

Given function is y = x sin 3x       …(1)

Differentiating the equation (1) with respect to x, we get …(2)

Differentiating the equation (2) with respect to x, we get  …(3)

Now, Thus, the given function y = x sin 3x is the solution of .

(iv) Check whether the function x2 = 2y2 log y is the solution of .

NCERT Solutions:

Given function is x2 = 2y2 log y       …(1)

Differentiating the equation (1) with respect to x, we get  …(2)

From (1), Thus, the given function x2 = 2y2 log y is the solution of .

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 3

Form the differential equation representing the family of curves given by (x – a)2 + 2y2 = a2, where a is an arbitrary constant.

NCERT Solutions:

Given equation is (x – a)2 + 2y2 = a2       …(1)

Differentiating (1) with respect to x, we get Putting in (1), we get Thus, the differential equation of the given equation is .

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 4

Prove that x2 – y2 = c (x2 + y2)2 is the general solution of differential equation (x3 – 3xy2) dx = (y3 – 3x2y) dy, where c is a parameter.

NCERT Solutions:

Given differential equation is …(1)

In equation (1), we see that dy/dx is in form of g(y/x), so it is a Homogeneous function of degree zero. Thus, the given differential equation is Homogeneous Differential Equation.

To solve this, we need to put y = vx                            …(2)

Differentiating the equation (2) with respect to x, we get On substituting y = vx and in equation (1), we get  On squaring both sides, we get x2 – y2 = c(x2 + y2)where c = C’2 is an arbitrary constant.

Thus, x2 – y2 = c(x2 + y2)2 is the general solution of the given differential equation.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 5

Form the differential equation of the family of circles in the first quadrant which touch the coordinate axes.

NCERT Solutions: Let the equation of the family of the circles which touch the co-ordinates axes in the first quadrant is

(x – a)2 + (y – a)2 = a2                    …(1)

, where a is the radius of the circle.

Differentiating (1) with respect to x, we get Substituting the value of ‘a’ in (1), we get This is required differential equation of the family of circles in the first quadrant which touch the coordinate axes.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 6

Find the general solution of the differential equation .

NCERT Solutions:

Given differential equation is .

Integrating both sides, we get This is required general solution of the given differential equation.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 7

Show that the general solution of the differential equation is given by (x + y + 1) = A (1 – x – y – 2xy), where A is parameter

NCERT Solutions:

Given differential equation is . Integrating both sides, we get  Thus, the general solution of the given differential equation is (x + y + 1) = A (1 – x – y – 2xy).

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 8

Find the equation of the curve passing through the point whose differential equation is sin x cos y dx + cos x sin y dy = 0.

NCERT Solutions:

Given differential equation is sin x cos y dx + cos x sin y dy = 0. Integrating both sides, we get –log |cos x| – log|cos y| = –log|C|

⇒ –log |cos x cos y| = –log|C|

⇒ cos x cos y = C

Since the curve passes through  Thus, This is required equation of the given curve.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 9

Find the particular solution of the differential equation (1 + e2x) dy + (1 + y2) ex dx = 0, given that y = 1 when x = 0.

NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 10

Solve the differential equation .

NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 11

Find a particular solution of the differential equation (x – y) (dx + dy) = dx – dy, given that y = –1, when x = 0. (Hint: put x – y = t)

NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 12

Solve the differential equation .

NCERT Solutions:

Given differential equation is …(1)

This equation is a type of , where .

Now, the Integrating Factor (IF) is .

Thus, the solution of the given differential equation is .

Putting the values of IF and Q, we get This is required general solution of the given differential equation.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 13

Find a particular solution of the differential equation (x ≠ 0), given that y = 0 when x = π/2

NCERT Solutions:

Given differential equation is …(1)

This equation is a type of , where P = cot x and Q = 4x cosec x.

Now, the Integrating Factor (IF) is .

Thus, the solution of the given differential equation is .

Putting the values of IF and Q, we get  This is required particular solution of the given differential equation.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 14

Find a particular solution of the differential equation (x + 1)(dy/dx) = 2 e–y – 1, given that y = 0 when x = 0.

NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 15

The population of a village increases continuously at the rate proportional to the number of its inhabitants present at any time. If the population of the village was 20, 000 in 1999 and 25000 in the year 2004, what will be the population of the village in 2009?

NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 16

The general solution of the differential equation is

(A) xy = C

(B) x = Cy2

(C) y = Cx

(D) y = Cx2

NCERT Solutions:

Given differential equation is  Integrating both sides, we get This is required general solution.

NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 17

The general solution of a differential equation of the type is NCERT Solutions: NCERT Solutions Class 12 Math Differential Equations Miscellaneous Exercise Ques No 18

The general solution of the differential equation ex dy + (yex + 2x) dx = 0 is

(A) x ey + x2 = C

(B) x ey + y2 = C

(C) y ex + x2 = C

(D) y ey + x2 = C

NCERT Solutions: error: Content is protected !!