Hi Students, Welcome to **Amans Maths Blogs (AMB)**. In this post, you will get the * NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.4*.

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**NCERT Solutions for Class 12 Maths Differential Equations Exercise 9.4*** NCERT Solutions for Class 12 Maths* are not only the solutions of Maths exercise but it builds your foundation of other important subjects. Getting knowledge of depth concept of

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**CBSE Class 12**^{th}Maths## NCERT Solutions for Class 12 Maths Differential Equations

For each of the differential equations in Exercises 1 to 10, find the general solution:

**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 1.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 2.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 3.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 4.**

sec^{2} x tan y dx + sec^{2} y tan x dy = 0

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 5.**

(e^{x} + e^{–x}) dy – (e^{x} – e^{–x}) dx = 0

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 6.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 7.**

y log y dx – x dy = 0

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 8.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 9.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 10.**

e^{x} tan y dx + (1 – e^{x}) sec^{2} y dy = 0

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For each of the differential equations in Exercises 11 to 14, find a particular solution satisfying the given condition:

**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 11.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 12.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 13.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 14.**

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 15.**

Find the equation of a curve passing through the point (0, 0) and whose differential equation is y′ = e^{x} sin x.

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 16.**

For the differential equation xy(dy/dx) = (x + 2)(y + 2), find the solution curve passing through the point (1, –1).

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 17.**

Find the equation of a curve passing through the point (0, –2) given that at any point (x, y) on the curve, the product of the slope of its tangent and y coordinate of the point is equal to the x coordinate of the point.

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 18.**

At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (– 4, –3). Find the equation of the curve given that it passes through (–2, 1).

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 19.**

The volume of spherical balloon being inflated changes at a constant rate. If initially its radius is 3 units and after 3 seconds it is 6 units. Find the radius of balloon after t seconds.

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 20.**

In a bank, principal increases continuously at the rate of r% per year. Find the value of r if Rs 100 double itself in 10 years (log_{e}2 = 0.6931).

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 21.**

In a bank, principal increases continuously at the rate of 5% per year. An amount of Rs 1000 is deposited with this bank, how much will it worth after 10 years (e^{0.5} = 1.648).

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 22.**

In a culture, the bacteria count is 1,00,000. The number is increased by 10% in 2 hours. In how many hours will the count reach 2,00,000, if the rate of growth of bacteria is proportional to the number present?

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**NCERT Solutions for Class 12 Maths Differential Equations ****Exercise**** 9.4: Ques No 23.**

The general solution of the differential equation dy/dx = e^{x+y }is

(A) e^{x} + e^{–y} = C

(B) e^{x} + e^{y} = C

(C) e^{–x} + e^{y} = C

(D) e^{–x} + e^{–y} = C

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