Contents

# JSTSE | MVPP 2020-21 Question Paper With Answer Keys And Solutions

Hi students, welcome to **AmansMathsBlogs (AMB)**. On this article, you will get **JSTSE MVPP 2020-21 Question Paper With Answer Keys And Solutions**.

**JSTSE 2020-21** is an exam that is conducted by science branch of the Directorate of Education, Government of Delhi. This exam is scheduled in Dec or Jan month of the session in every year. But, due to Covid-19 in India, this year, in 2020-21 session, **JSTSE **is conducted on 28 March 2021 (Sunday). From 2021, JSTSE (Junior Science Talent Search Examination) is now known as MVPP (Mukhyamantri Vigyan Pratibha Pariksha).

The math questions of **JSTSE MVPP 2020-21 Question Paper With Answer Keys And Solutions** are solved by me, AMAN RAJ, I am maths faculty of IIT Maths Foundation course and founder of this website **AmansMathsBlogs (AMB)**.

**Read More :** **129 Maths Short Tricks**

## JSTSE | MVPP 2020-21 MAT & SAT Question Paper

## JSTSE MAT 2020-21 Answer Keys: PART – I

JSTSE | MVPP MAT Answer Keys | |||||||
---|---|---|---|---|---|---|---|

Ques No | Ans Key | Ques No | Ans Key | Ques No | Ans Key | Ques No | Ans Key |

1 |
4 |
26 |
2 |
51 |
3 |
76 |
2 |

2 |
2 |
27 |
3 |
52 |
2 |
77 |
1 |

3 |
1 |
28 |
4 |
53 |
4 |
78 |
1 |

4 |
4 |
29 |
3 |
54 |
1 |
79 |
3 |

5 |
2 |
30 |
1 |
55 |
2 |
80 |
4 |

6 |
1 |
31 |
3 |
56 |
2 |
81 |
2 |

7 |
3 |
32 |
3 |
57 |
3 |
82 |
2 |

8 |
4 |
33 |
1 |
58 |
3 |
83 |
3 |

9 |
3 |
34 |
2 |
59 |
2 |
84 |
3 |

10 |
3 |
35 |
3 |
60 |
3 |
85 |
3 |

11 |
4 |
36 |
4 |
61 |
4 |
86 |
4 |

12 |
3 |
37 |
1 |
62 |
3 |
87 |
2 |

13 |
4 |
38 |
2 |
63 |
2 |
88 |
4 |

14 |
3 |
39 |
2 |
64 |
2 |
89 |
1 |

15 |
3 |
40 |
3 |
65 |
3 |
90 |
4 |

16 |
2 |
41 |
1 |
66 |
4 |
91 |
2 |

17 |
1 |
42 |
1 |
67 |
1 |
92 |
3 |

18 |
3 |
43 |
3 |
68 |
4 |
93 |
4 |

19 |
2 |
44 |
3 |
69 |
2 |
94 |
2 |

20 |
4 |
45 |
2 |
70 |
4 |
95 |
2 |

21 |
2 |
46 |
2 |
71 |
1 |
96 |
4 |

22 |
4 |
47 |
4 |
72 |
2 |
97 |
2 |

23 |
4 |
48 |
2 |
73 |
1 |
98 |
3 |

24 |
2 |
49 |
4 |
74 |
1 |
99 |
1 |

25 |
1 |
50 |
2 |
75 |
3 |
100 |
2 |

## JSTSE SAT 2020-21 Answer Keys: PART – II

JSTSE | MVPP SAT Answer Keys | |||||||
---|---|---|---|---|---|---|---|

Ques No | Ans Key | Ques No | Ans Key | Ques No | Ans Key | Ques No | Ans Key |

101 |
3 |
126 |
4 |
151 |
4 |
176 |
3 |

102 |
1 |
127 |
3 |
152 |
4 |
177 |
2 |

103 |
3 |
128 |
1 |
153 |
2 |
178 |
4 |

104 |
3 |
129 |
3 |
154 |
1 |
179 |
2 |

105 |
1 |
130 |
2 |
155 |
4 |
180 |
3 |

106 |
1 |
131 |
2 |
156 |
4 |
181 |
1 |

107 |
2 |
132 |
1 |
157 |
1 |
182 |
1 |

108 |
1 |
133 |
3 |
158 |
3 |
183 |
3 |

109 |
2 |
134 |
4 |
159 |
3 |
184 |
1 |

110 |
1 |
135 |
3 |
160 |
3 |
185 |
2 |

111 |
4 |
136 |
4 |
161 |
1 |
186 |
3 |

112 |
1 |
137 |
2 |
162 |
4 |
187 |
1 |

113 |
1 |
138 |
1 |
163 |
2 |
188 |
3 |

114 |
2 |
139 |
1 |
164 |
3 |
189 |
1 |

115 |
2 |
140 |
3 |
165 |
4 |
190 |
3 |

116 |
3 |
141 |
2 |
166 |
3 |
191 |
3 |

117 |
2 |
142 |
3 |
167 |
3 |
192 |
2 |

118 |
4 |
143 |
1 |
168 |
4 |
193 |
1 |

119 |
3 |
144 |
4 |
169 |
1 |
194 |
4 |

120 |
3 |
145 |
2 |
170 |
1 |
195 |
3 |

121 |
3 |
146 |
3 |
171 |
3 |
196 |
1 |

122 |
3 |
147 |
1 |
172 |
3 |
197 |
2 |

123 |
2 |
148 |
3 |
173 |
2 |
198 |
1 |

124 |
1 |
149 |
1 |
174 |
2 |
199 |
2 |

125 |
2 |
150 |
1 |
175 |
1 |
200 |
3 |

## JSTSE | MVPP 2020-21 Answer Keys With Solutions (SAT-Math)

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 141**

If x + y + z = 0, then find the value of (x4 + y^{4} + z^{4}/(x^{2}y^{2} + y^{2}z^{2} + z^{2}x^{2}) is

**Options:**

1. 1/2

2. 2

3. 3xyz

4. 3x^{2}y^{2}z^{2}

**Answer Key: 2**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 142**

If x^{a} = y^{2b} = z^{3c} and y^{2} = zx, then find the value of 1/a + 1/3c is

**Options:**

1. b/2

2. b

3. 1/b

4. 2/b

**Answer Key: 3**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 143**

If m = 2^{1/3} + 2^{-1/3}, then find the value of 2m^{3} – 6m + 1 is

**Options:**

1. 6

2. 2

3. 3

4. 4

**Answer Key: 1**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 144**

The coefficient of p^{2} in (p^{2} + 2p + 3)^{2} + (p^{2} – 2p + 3)^{2} is

**Options:**

1. 6

2. 10

3. 18

4. 20

**Answer Key: 4**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 145**

Factorize the following : a^{3} + 3a^{2}b + 3ab^{2} + 2b^{3}.

**Options:**

1. (2a + b)(a^{2} + ab + b^{2})

2. (a + 2b)(a^{2} + ab + b^{2})

3. (2a + b)(a^{2} + 3ab + b^{2})

4. (a + 2b)(a^{2} + 3ab + b^{2})

**Answer Key: 2**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 146**

If a = ∛64 and b = ∛65, then find the value of (a + b) – 1/(a^{2} + ab + b^{2}).

**Options:**

1. 2

2. 4

3. 8

4. 16

**Answer Key: 3**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 147**

If 9K+2 – 240 = 9K, then the value of (18K)^{K} is

**Options:**

1. 3

2. 9

3. 3√2

4. 2√3

**Answer Key: 1**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 148**

If z = 3 + 3^{1/3} + 3^{2/3}, then find the value of z^{3} – 9z^{2} + 18z – 7.

**Options:**

1. 12

2. 10

3. 5

4. -5

**Answer Key: 3**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 149**

If L : M : N = 2 : 3 : 4 and L^{2} + M^{2} + N^{2} = 11600, then find the value of L + M – N.

**Options:**

1. 20

2. 60

3. 100

4. 180

**Answer Key: 3**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 150**

If p + q + r = 2, pq + qr + rp = -1 and pqr = -2, then find the value of p^{3} + q^{3} + r^{3}.

**Options:**

1. 8

2. -8

3. 16

4. -16

**Answer Key: 1**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 151**

If a = √2 – √6, b = √6 – √3 and c = √3 – √2, then find the value of a^{3} + b^{3} + c^{3} – 2abc is

**Options:**

1. 0

2. √2 + √3 + √6

3. 5√3 – √6 + 3√2

4. 3√2 + √6 – 4√3

**Answer Key: 4**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 152**

Factorize : x^{2}y + xz^{2} + y^{2}z – x^{2}z – y^{2}x – z^{2}y.

**Options:**

1. (x + y)(y + z)(z + x)

2. (x – y)(y + z)(z – x)

3. (x – y)(y – z)(z – x)

4. (x – y)(y – z)(x – z)

**Answer Key: 4**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 153**

In the given figure, XZ = ZY = XT, then the value of x is

**Options:**

1. 30

2. 33

3. 49

4. 49.5

**Answer Key: 2**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 154**

If a + b = m and 1/a + 1/b = 1/n, then relationship in m, n and a is

**Options:**

1. m(a – n) = a^{2}

2. m(a + n) = a^{2}

3. a(m – n) = a^{2}

4. a(m + n) = n^{2}

**Answer Key: 1**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 155**

If x = 0.473 (bar over 73), then find the value of x + 1.6 (bar over 6).

**Options:**

1. 2.140 (bar over 140)

2. 0.2140 (bar over 40)

3. 21.40 (bar over 40)

4. 2.140 (bar over 40)

**Answer Key: 4**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 156**

Area of the quadrilateral REST, in which angle R = 90 degree, RE = 30 cm, ES = 42 cm, ST = 20 cm and TR = 16 cm is

**Options:**

1. 192 sq. cm

2. 240 sq. cm

3. 336 sq. cm

4. 576 sq. cm

**Answer Key: 4**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 157**

A train of length 240 cm, crosses a platform in 20 seconds. If the speed of the train is 72 km/hr., then the length of platform is

**Options:**

1. 160 m

2. 180 m

3. 240 m

4. 260 m

**Answer Key: 1**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 158**

In given figure, ABC is an equilateral triangle of side 8 cm. Find the area of shaded region.

**Options:**

1. 32 – 16π/3 sq. cm

2. 32 – 8π/3 sq. cm

3. 16√3 – 8π sq. cm

4. 32√3 – 16π sq. cm

**Answer Key: 3**

**Solution:**

**MVPP 2020-21 Question Paper With Answer Keys and Solution: Ques No 159**

Mean of 9 observation was found to be 35. Later on, it was detected that an observation 80 was missed as 8. The correct mean is

**Options:**

1. 45

2. 44

3. 43

4. 42

**Answer Key: 3**

**Solution:**

**JSTSE 2020-21 Question Paper With Answer Keys and Solution: Ques No 160**

If (3√2 + 2√3)/(4√2 + 3√3) = p + q√6, then find the value of p and q.

**Options:**

1. p = 1/5 and q = 6/5

2. p = 6/5 and q = 1/5

3. p = 6/5 and q = -1/5

4. p = -6/5 and q = 1/5

**Answer Key: 3**

**Solution:**