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CUET Physics Mock Test Electric Charges and Fields AMBIPi

Hi CUET aspirants, Welcome to Amans Maths Blogs (AMBIPi). In this post, you will get CUET Physics Mock Test Electric Charges and Fields AMBIPi. This CUET Physics Mock Test is of the Physics chapter Electric Charges and Fields. Before solving these CUET Physics questions, you must read CUET Physics Notes, which helps you to revise CUET Physics Syllabus and then you must need to solve CUET Previous Years Questions Papers.

CUET Physics Mock Test

CUET Physics Question No: 1

When the distance between the charged particles is halved, the force between them becomes.

Option A : One-fourth

Option B : Half

Option C : Double

Option D : Four times

Show/Hide Answer Key

Option D: Four times

Since f ∝ 1/d2, when r is halved the force becomes four times.

CUET Exam Physics Question No: 2

A charge q1 exerts some force on a second charge q2 . If third charge q3 is brought near, the force of q1 exerted on q2.

Option A : Decreases

Option B : Increases

Option C : Remains unchanged

Option D : Increases if q3 is of the same signs as q1 and decreases if q3 is of opposite sign.

Show/Hide Answer Key

Option C: Four times Remains unchanged

The force will still remain unchanged.

CUET UG Physics Question No: 3

The minimum charge on an object is

Option A : 1 coulomb

Option B : 1 stat coulomb

Option C : 1.6 × 10–19 coulomb

Option D : 3.2 × 10–19 coulomb

Show/Hide Answer Key

Option C: 1.6 × 10–19 coulomb

All other charges are its integral multiple. Minimum charge on an object = 1.6 × 10–19 coulomb.

CUET Domain Subject Physics Question No: 4

Three charges 4q, Q and q are in a straight line in the position of 0, 1/2 and 1 respectively. The resultant force on q will be zero, if Q =

Option A : -q

Option B : -2q

Option C : -q/2

Option D : 4q

Show/Hide Answer Key

Option A: -q

The force between 4q and q.

The force between Q and q

CUET BSc Physics Question No: 5

The number of electrons in 1.6 C charge will be

Option A : 1019

Option B : 1020

Option C : 1.1 × 1019

Option D : 1.1 × 102

Show/Hide Answer Key

Option A: 1019

CUET Entrance Exam Physics Question No: 6

The electric charge in uniform motion produces

Option A : An electric field only

Option B : A magnetic field only

Option C : Both electric and magnetic field

Option D : Neither electric nor magnetic field

Show/Hide Answer Key

Option C: Both electric and magnetic field

A movable charge produces electric field and magnetic field both

CUET Exam Question No: 7

Figure shows the electric lines of force emerging from a charged body. If the electric field at A and B are EA and EB respectively and if the displacement between A and B is r, then

Option A : EA > EB

Option B : EA < EB

Option C : EA = EB / r

Option D : EA = EB / r2

Show/Hide Answer Key

Option A: EA > EB

In non-uniform electric field. Intensity is more, where the lines are more denser.

CUET Physics Practice Questions No: 8

The electric field near a conducting surface having a uniform surface charge density is given by

Option A : σ/εo and is parallel to the surface

Option B : 2σ/εo and is parallel to the surface

Option C : σ/εo and is normal to the surface

Option D : 2σ/εo and is normal to the surface

Show/Hide Answer Key

Option C: σ/εo and is normal to the surface

Electric field near the conductor surface is given by σ/εo and it is perpendicular to surface.

CUET Physics Sample Paper Question No: 9

Deutron and -particle are put 1 Å apart in air. Magnitude of intensity of electric field due to deutron at -particle is

Option A : zero

Option B : 2.88 × 1011 N/C

Option C : 1.44 × 1011 N/C

Option D : 5.76 × 1011 N/C

Show/Hide Answer Key

Option C: 1.44 × 1011 N/C

Due to deutron, intensity of electric field at 1 Å distance.

CUET Physics Mock Test Question No: 10

An electric dipole when placed in a uniform electric field E will have minimum potential energy, if the positive direction of dipole moment makes the following angle with E

Option A : π

Option B : π/2

Option C : Zero

Option D : 3π/2

Show/Hide Answer Key

Option C: Zero

Potential energy = –pE cosθ

When θ = 0

Potential energy = –pE (minmum)

CUET Physics Question No: 11

The electric potential at a point on the axis of an electric dipole depends on the distance r of the point from the dipole as

Option A : ∝ 1/ r

Option B : ∝ 1/ r2

Option C : ∝ r

Option D : ∝ 1/ r3

Show/Hide Answer Key

Option B: ∝ 1/ r2

Electric potential due to dipole in it’s general position is given by

CUET Exam Physics Question No: 12

An electric dipole is kept in non-uniform electric field. It experiences

Option A : A force and a torque

Option B : A force but not a torque

Option C : A torque but not a force

Option D : Neither a force nor a torque

Show/Hide Answer Key

Option A: A force and a torque

As the dipole will feel two forces which are although opposite but not equal.

Thus, A net force will be there and as these forces act at different points of a body. A torque is also parent.

CUET UG Physics Question No: 13

The distance between the two charges +q and –q of a dipole is r. On the axial line at a distance d from the centre of dipole, the intensity is proportional to

Option A : q/d2

Option B : qr/d2

Option C : q/d3

Option D : qr/d3

Show/Hide Answer Key

Option D: qr/d3

Field along the axis of the dipole

CUET Domain Subject Physics Question No: 14

The electric field due to an electric dipole at a distance r from its centre in axial position is E. If the dipole is rotated through an angle of 90° about its perpendicular axis, the electric field at the same point will be

Option A : E

Option B : E / 4

Option C : E / 2

Option D : 2E

Show/Hide Answer Key

Option C: E/2

When the dipole is rotated through at an angle of 90° about it’s perpendicular axis then given point comes out to be on equator. So field will become E / 2 at the given point.

CUET BSc Physics Question No: 15

An electric dipole of moment ρ placed in a uniform electric field E has minimum potential energy when the angle between ρ and E is

Option A : Zero

Option B : π/2

Option C : π

Option D : 3π/2

Show/Hide Answer Key

Option A: Zero

U = –PE cos θ. It has minimum value when θ= 0°. i.e. Umin = –PE cos0° = –PE

CUET Entrance Exam Physics Question No: 16

A Cylinder of radius R and length L is placed in a uniform electric field E parallel to the cylinder axis. The total flux for the surface of the cylinder is given by

Option A : 2πR2E

Option B : πR2 / E

Option C : (πR2/ πR) / E

Option D : Zero

Show/Hide Answer Key

Option C: Both electric and magnetic field

Flux through surface A ΦA = E × πR2 and ΦB = E × πR2.

Flux through curved surface

Total flux through cylinder = ΦA + ΦB + ΦC = 0

CUET Exam Question No: 17

An electric charge q is placed at the centre of a cube of side a. The electric flux on one of its faces will be

Option A : q / 6εo

Option B : q / εoa2

Option C : q / 4πεoa2

Option D : q / εo

Show/Hide Answer Key

Option A: q / 6εo

By Gauss’s theorem, Electric flux φ = q / 6εo

CUET Physics Practice Questions No: 18

For a given surface the Gauss’s law is stated as ∮E.ds = 0. From this we can conclude that

Option A : E is necessarily zero on the surface

Option B : E is perpendicular to the surface at every point

Option C : The total flux through the surface is zero

Option D : The flux is only going out of the surface

Show/Hide Answer Key

Option C: The total flux through the surface is zero

The total flux through the surface is zero.

CUET Physics Sample Paper Question No: 19

Total electric flux coming out of a unit positive charge put in air is

Option A : εo

Option B : εo-1

Option C : (4ρεo)-1

Option D : 4πεo

Show/Hide Answer Key

Option B: εo-1

Total flux coming out from unit charge

CUET Physics Mock Test Question No: 20

A cube of side l is placed in a uniform field E, where E = Eiˆ. The net electric flux through the cube is

Option A : Zero

Option B : l2E

Option C : 4l2E

Option D : 6l2E

Show/Hide Answer Key

Option A: Zero

As there is no charge residing inside the cube, hence net flux is zero.

CUET Physics Question No: 21

A charge q is placed at the centre of the open end of cylindrical vessel. The flux of the electric field through the surface of the vessel is

Option A : Zero

Option B : q/εo

Option C : q/2εo

Option D : 2q/εo

Show/Hide Answer Key

Option D: Four times

To apply Gauss’s theorem it is essential that charge should be placed inside a closed surface. So, imagine another similar cylindrical vessel above it as shown in figure (dotted).

Required flux φ = q/2εo

CUET Exam Physics Question No: 22

According to Gauss’s Theorem, electric field of an infinitely long straight wire is proportional to

Option A : r

Option B : 1/r

Option C : 1/r3

Option D : 1/r

Show/Hide Answer Key

Option D: 1/r

CUET UG Physics Question No: 23

The S.I. unit of electric flux is

Option A : Weber

Option B : Newton per coulomb

Option C : Volt × meter

Option D : Joule per coulomb

Show/Hide Answer Key

Option C: Volt × meter

S.I. unit of electric flux is

CUET Domain Subject Physics Question No: 24

Gauss’s law is true only if force due to a charge varies as

Option A : r-1

Option B : r-2

Option C : r-3

Option D : r-4

Show/Hide Answer Key

Option B: r-2

Gauss’s law is true only if force due to a charge varies as r–2.

CUET BSc Physics Question No: 25

An electric dipole is put in north-south direction in a sphere filled with water. Which statement is correct

Option A : Electric flux is coming towards sphere

Option B : Electric flux is coming out of sphere

Option C : Electric flux entering into sphere and leaving the sphere are same

Option D : Water does not permit electric flux to enter into sphere.

Show/Hide Answer Key

Option C: Electric flux entering into sphere and leaving the sphere are same

In electric dipole the flux coming out from positive charge is equal to the flux coming in at negative charge i.e. total charge on sphere = 0. From Gauss law, total flux passing through the sphere = 0.

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