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SSC CGL Tier 1 Math Previous Year Number System Question with Solutions

Hi students, Welcome to Amans Maths Blogs (AMBIPi). Are you preparing for SSC CGL Tier 1 and 2 and looking for SSC CGL Exam Math Number System Question with Solutions AMBIPi? In this article, you will get Previous Year Mathematics Questions asked in SSC CGL Tier 1 and Tier 2, which helps you in the preparation of government job exams of SSC CGL.

SSC CGL Exam Math Number System Question with Solutions

SSC CGL Exam Math Question: 1

If two numbers x and y separately divided by a number d, remainders obtained are 4375 and 2986 respectively. If the sum of the numbers i.e (x+y) is divided by the same number d remainder obtained is 2361. The value of number d is

Option A : 7361

Option B : 5000 

Option C : 4000

Option D : 2542 

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Option B : 5000

d = 4375 + 2986 – 2361
= 5000

SSC CGL Previous Year Math Questions: 2

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. A student attempted all the 200 questions and scored in all 200 marks. The number of questions, he answered correctly was

Option A :82 

Option B :80 

Option C :68 

Option D :60 

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Option B : 80

x = 400/5 = 80

SSC CGL Previous Year Math Paper: 3

In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 75 questions and secures 125 marks, the number of questions he attempts correctly is

Option A : 35

Option B : 40

Option C : 42

Option D : 46

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Option B : 40

Let the number of correct answers be x.

x = 200/5 = 40

SSC CGL Mock Test Math Question: 4

The product of two positive numbers is 2500. If one number is four times the other, the sum of the two numbers is :

Option A : 25

Option B : 125

Option C : 225

Option D : 250

Show/Hide Answer Key

Option B: 125

SSC CGL Free Mock Test Math Question: 5

Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is :

Option A : 15

Option B : 20

Option C : 25

Option D : 10

Show/Hide Answer Key

Option B : 20

If the number of correct sums
be x, then,

x = 20

SSC CGL Advance Math Question: 6

If a * b = a + b + ab, then the value of 12 * 4 is

Option A : 20

Option B : 21

Option C : 48

Option D : 19

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Option D : 19

16 + 3 = 19

SSC CGL Math Previous Year Question: 7

Find the maximum number of trees which can be planted, 20 metres apart, on the two sides of a straight road 1760 metres long

Option A : 180

Option B : 178

Option C : 174

Option D : 176

Show/Hide Answer Key

Option B : 178

Number of trees on each side of the road [+1 because we would start with a tree]

Required answer
= 89 × 2 = 178

SSC CGL Math Question Paper: 8

A and B have together three times what B and C have, while A, B, C together have thirty rupees more than that of A. If B has 5 times that of C, then A has

Option A : 60

Option B : 65

Option C : 75

Option D : 45

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Option B : 65

Advance Math Question Asked in SSC CGL: 9

A number is doubled and 9 is added. If the resultant is trebled, it becomes 75. What is that number ?

Option A : 6

Option B : 3.5

Option C : 8

Option D : None of these

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Option C : 8

6x = 48 Þ x = 8

Previous Year Math Question Paper SSC CGL: 10

If a certain number of two digits is divided by the sum of its digits, the quotient is 6 and the remainder is 3. If the digits are reversed and the resulting number is divided by the sum of the digits, the quotient is 4 and the remainder is 9. The sum of the digits of the number is

Option A : 6

Option B : 9

Option C : 12

Option D : 4

Show/Hide Answer Key

Option C : 12

Let the number be 10x + y.
Dividend = Divisor × quotient +
remainder

From equation (ii),
2 × 5 – x = 3 Þ
x = 10 – 3 = 7
Sum of digits = x + y = 7 + 5 =12

SSC CGL Exam Math Number System Question: 11

Natu and Buchku each have certain number of oranges. Natu says to Buchku, “If you give me 10 of your oranges, I will have twice the number of oranges left with you”. Buchku replies,“If you give me 10 of your oranges, I will have the same number of oranges as left with you”. What is the number of oranges with Natu and Buchku, respectively ?

Option A : 50, 20

Option B : 70, 50

Option C : 20, 50

Option D : 50, 70

Show/Hide Answer Key

Option B : √1.44

Let the number of oranges
with Natu be x. Number of oranges with Buch-ku = y 

From equation (ii),
x – 50 = 20
Þ x = 50 + 20 = 70

SSC CGL Previous Year Math Number System Questions: 12

The numbers 2272 and 875 are divided by a 3-digit number N, giving the same remainders. The sum of the digits of N is

Option A : 10

Option B : 11

Option C : 12

Option D : 13

Show/Hide Answer Key

Option A : 10

Let the remainder in each case
be x.
Then, (2272 – x) and (875 – x)
are exactly divisible by that three digit number. Hence, their difference [(2272 –x) – (875 – x)] = 1397 will also be exactly divisible by the said divisor (N).
Now, 1397 = 11×127. Since both 11 and 127 are prime
numbers, N is 127.
Sum of digits = 1+ 2 + 7 = 10

SSC CGL Previous Year Math Number System Paper: 13

A 2-digit number is 3 times the sum of its digits. If 45 is added to the number, its digits are interchanged. The sum of digits of the number is

Option A : 11

Option B : 9

Option C : 7

Option D : 5

Show/Hide Answer Key

Option B : 9

Let the two digit number be =
10x + y. 

From equation (ii),
y –2 = 5 Þ y = 2 + 5 = 7
Number = 10x + y
= 2 × 10 +7 = 27
Sum of digits = 2 + 7 = 9

SSC CGL Mock Test Math Number System Question: 14

7 is added to a certain number; the sum is multiplied by 5; the product is divided by 9 and 3 is subtracted from the quotient. Thus if the remainder left is 12, what was the original number ?

Option A : 30

Option B : 20

Option C : 40

Option D : 60

Show/Hide Answer Key

Option B : 20

Check through options
20 ® 20 + 7 = 27 ® 27 × 5
= 135 ® 135 ÷ 9
= 15 ®15 – 3 = 12
OR, We will solve the problem
from the opposite side.
Here the remainder is 12.

The original number was 20.

SSC CGL Free Mock Test Math Number System Question: 15

If the difference of two numbers is 3 and the difference of their squares is 39, then the larger  number is

Option A : 8

Option B : 9

Option C : 12

Option D : 13

Show/Hide Answer Key

Option A : 8

Let the numbers be a and b,
where a > b
According to the question,
a – b = 3

Adding equations (i) and (ii)
2a = 16 Þ a = 8

SSC CGL Advance Math Number System Question: 16

How many numbers less than 1000 are multiples of both 10 and 13

Option A : 9

Option B : 8

Option C : 6

Option D : 7

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Option D : 7

The number of multiples of
130 are obtained by dividing
1000 by 130. The quotient i.e. 7
gives the result.

SSC CGL Math Previous Year Number System Question: 17

A two digit number is five times the sum of its digits. If 9 is added to the number, the digits interchange their positions. The sum of digits of the number is

Option A : 11

Option B : 9

Option C : 7

Option D : 6

Show/Hide Answer Key

Option B : 9

Let the two digit number be
10y + x. 

Number = 10 × 4 + 5 = 45
Sum of digits = 4 + 5 = 9

SSC CGL Math Number System Question Paper: 18

Of the three numbers, the second is twice the first and it is also thrice the third. If the average of three numbers is 44, the difference of the first number and the third number is :

Option A : 24

Option B : 18

Option C : 12

Option D : 6

Show/Hide Answer Key

Option C : 12

Advance Math Number System Question Asked in SSC CGL: 19

380 mangoes are distributed among some boys and girls who are 85 in number. Each boy gets four mangoes and each girl gets five. The number of boys is

Option A : 15

Option B : 38

Option C : 40

Option D : 45

Show/Hide Answer Key

Option D : 45

Let number of boys = x
and number of girls = 85 – x =

12

Previous Year Math Number System Question Paper SSC CGL: 20

The product of two numbers is 120. The sum of their squares is 289. The difference of these two numbers is

Option A : 9

Option B : 7

Option C : 8

Option D : 6

Show/Hide Answer Key

Option B : 7

Let the numbers be x and y.
xy = 120  

x – y = 7

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