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# Simplification Questions Set 1 | For SSC CGL | SSC CHSL | IBPS | RRB # Simplification Questions Set 1 For SSC CGL | CHSL | IBPS | RRB

There are following important simplification questions for SSC CGL, SSC CHSL, IBPS Bank & RRB Railways Exams. In the simplification questions, you are not expected to calculate the exact value.

Simplification Questions Set 1 for SSC CGL : Ques No 1

If (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7) = p, then the value of p is

Options:

A. 0.44

B. 0.32

C. 0.49

D. 1.6

Simplification Questions Set 1 for SSC CHSL : Ques No 2

If 15% of 62.5 + 10% of 4.80 = k, then the value of k is

Options:

A. 14.18

B. 15.20

C. 10

D. 16

Simplification Questions Set 1 for IBPS Bank : Ques No 3

Evaluate 543.28 ÷ 55

Options:

A. 4

B. 8

C. 10

D. 12

Simplification Questions Set 1 for RRB : Ques No 4

If [(3 / 0.8) × (11 / 0.2)] ÷ [(28 / 3) × (21 / 5)] = m, then the value of m is

Options:

A. 3

B. 5

C. 7

D. 9

Simplification Questions Set 1 for SSC CGL : Ques No 5

If (1.1)2 + (3.2)2 + (3.0)2 = x, then the value of x is

Options:

A. 20

B. 22

C. 24

D. 25

Simplification Questions Set 1 for SSC CHSL : Ques No 6

If (7895641 ÷ 2795 ÷ 123) × 345 ÷ 456 = y, then the value of y is

Options:

A. 17

B. 25

C. 10

D. 30

Simplification Questions Set 1 for IBPS Bank : Ques No 7

If 3945 + 150 × 40 – 35.5 = a, then the value of a is

Options:

A. 9000

B. 10000

C. 9500

D. 9900

Simplification Questions Set 1 for RRB : Ques No 8

Evaluate (63)2 × 3.545 :

Options:

A. 14070

B. 15080

C. 13040

D. 14089

Simplification Questions Set 1 for SSC CGL : Ques No 9

If 3.5 × 0.07 ÷ (1.7)2 = x, then the value of x is

Options:

A. 4

B. 3

C. 1

D. 5

Simplification Questions Set 1 for SSC CHSL : Ques No 10

If 64% of 159.96 + 72% of 65.005 + (1.4)2 – (0.4)2 = k, then the value of k is

Options:

A. 131

B. 141

C. 151

D. 161

Simplification Questions Set 1 for IBPS Bank : Ques No 11

If 2567 ÷ 17 × 3 = x + 180, then the value of x is

Options:

A. 51

B. 271

C. 273

D. 71

Simplification Questions Set 1 for RRB : Ques No 12

If 7.5% of 140 + 2.5% of 80 = k, then the value of k is

Options:

A. 12.5

B. 13.5

C. 14.5

D. 15.5

Simplification Questions Set 1 for SSC CGL : Ques No 13

If 3/5 of 4/7 of 7/12 of 1375 = b, then the value of b is

Options:

A. 185

B. 175

C. 285

D. 275

Simplification Questions Set 1 for SSC CHSL : Ques No 14

If 32.05 × 15 + d = 500, then the value of d is

Options:

A. 19.75

B. 19.25

C. 20.75

D. 20.25

Simplification Questions Set 1 for IBPS Bank : Ques No 15

If 107.5 × 52.5 × 22.5 = 10x, then the value of x is

Options:

A. 10

B. 12.5

C. 9.5

D. 11.5

Simplification Questions Set 1 for RRB : Ques No 16

If 1 (8/9) + 3 (2/7) – 2 (1/7) + 11 (1/6) = k, then the value of k is

Options:

A. 7 12/223

B. 14 25/223

C. 14 25/126

D. 7 11/126

Simplification Questions Set 1 for SSC CGL : Ques No 17

If 56% of 958 + 67% of 1008 = p% of 2000, then the value of p is

Options:

A. 60.592

B. 47.622

C. 42.86

D. 91.455

Simplification Questions Set 1 for SSC CHSL : Ques No 18

If 72.3 × 494.7 × 633.4 × 815.85 = 63k, then the value of k is

Options:

A. 16.25

B. 15.1

C. 13.4

D. 18.9

Simplification Questions Set 1 for IBPS Bank : Ques No 19

If (x)²+ (164)² = (307)² – 272, then the value of x is

Options:

A. 151

B. 189

C. 211

D. 259

Simplification Questions Set 1 for RRB : Ques No 20

If √(915849) + √(795664)= (k)², then the value of k is

Options:

A. 1849

B. 2809

C. 53

D. 43

Simplification Questions Set 1 for SSC CGL : Ques No 21

If 6399 × 1(5/8) + 353 ÷ x = 10444, then the value of x is

Options:

A. 14

B. 22

C. 2

D. 8

Simplification Questions Set 1 for SSC CHSL : Ques No 22

If √(624) × 14.02 + √(404) × 15.97 = x, then the value of x is

Options:

A. 670

B. 570

C. 710

D. 510

Simplification Questions Set 1 for IBPS Bank : Ques No 23

If 8461 ÷ 11.99 – 24.01 ÷ (5 / 100) = k, then the value of k is

Options:

A. 625

B. 400

C. 225

D. 900

Simplification Questions Set 1 for RRB : Ques No 24

If (14.85% of 679) + (19.9% of 219.83) = p, then the value of p is

Options:

A. 115

B. 145

C. 65

D. 105

Simplification Questions Set 1 for SSC CGL : Ques No 25

If 1441 ÷ k + 149.98 × 14.99 = 3006 – 254.91, then the value of k is

Options:

A. 3

B. 15

C. 25

D. 45

Simplification Questions Set 1 for SSC CHSL : Ques No 26

If 8(1 / 2) + 4(2 / 7) = 5(1 / 2) + x, then the value of x is

Options:

A. 8 (1/7)

B. 6 (1/7)

C. 7 (2/7)

D. 5 (1/7)

Simplification Questions Set 1 for IBPS Bank : Ques No 27

If 58.4 × 1.5 × 2.2 + x = 376, then the value of x is

Options:

A. 175.82

B. 185.08

C. 183.28

D. 193.28

Simplification Questions Set 1 for RRB : Ques No 28

If (46% of 1250) + p % of 4680 = 1183.4, then the value of p is

Options:

A. 18

B. 13

C. 22

D. 24

Simplification Questions Set 1 for SSC CGL : Ques No 29

If √2916 – √1681 = √x + 9.5, then the value of x is

Options:

A. 18.25

B. 21.05

C. 12.25

D. 20.25

Simplification Questions Set 1 for SSC CHSL : Ques No 30

If 4642 + 2368 + 142 – x = 5986, then the value of x is

Options:

A. 1620

B. 1420

C. 1120

D. 1220

Simplification Questions Set 1 for IBPS Bank : Ques No 31

If 9.5 ÷ 1.9 × 2.6 + 3.8 ÷ 1.9 × 2.5 = d, then the value of d is

Options:

A. 17

B. 18

C. 14

D. 16

Simplification Questions Set 1 for RRB : Ques No 32

If 5.4 × 3.2 × 6.2 × (1.5)2 = d, then the value of d is

Options:

A. 133.856

B. 133.946

C. 133.546

D. 241.056

Simplification Questions Set 1 for SSC CGL : Ques No 33

If 54% of 680 + 24% of 280 – 12% of 120 = k, then the value of k is

Options:

A. 320

B. 520

C. 440

D. 420

Simplification Questions Set 1 for SSC CHSL : Ques No 34

If 78% of 625 + 35% of 450 = x %of 2150, then the value of x is

Options:

A. 30

B. 40

C. 35

D. 50

Simplification Questions Set 1 for IBPS Bank : Ques No 35

If 4(5 / 2) + 5(4 / 2) + 6(3 / 2) – 9(1 / 2) = x, then the value of x is

Options:

A. 7 (1/2)

B. 6 (1/2)

C. 11 (1/2)

D. 7 (1/2)

Simplification Questions Set 1 for RRB : Ques No 36

If 3√13824 + √1849 = 3√9261 + √x, then the value of x is

Options:

A. 1256

B. 1936

C. 2116

D. 2456

Simplification Questions Set 1 for SSC CGL : Ques No 37

If (0.8) / (0.2)2 × (0.6)2 = (2.4)2 × k, then the value of k is

Options:

A. 1.8

B. 1.4

C. 1.25

D. 1.6

Simplification Questions Set 1 for SSC CHSL : Ques No 38

If 7654.32 + 8962.81 + 3432.12 – 512.32 + 212.82 + 316.84 = x, then the value of x is

Options:

A. 20056.49

B. 20046.79

C. 20065.49

D. 20066.59

Simplification Questions Set 1 for IBPS Bank : Ques No 39

If 812 + 912 + 516 + 241 + 346 + 329 = 12 × k, then the value of k is

Options:

A. 263

B. 265

C. 326

D. 363

Simplification Questions Set 1 for RRB : Ques No 40

If 4√1296 + 4√2401 + 4√6561 – 4√256 = p, then the value of p is

Options:

A. 14

B. 18

C. 22

D. 16

Simplification Questions Set 1 for SSC CGL : Ques No 41

If 2 (1/6) + [3(3/4) – 1(1/4)] = k, then the value of k is

Options:

A. 4 (5/12)

B. 4 (2/3)

C. 4 (7/12)

D. 5 (3/12)

Simplification Questions Set 1 for SSC CHSL : Ques No 42

If 36251 + 43261 = x + 52310, then the value of x is

Options:

A. 27202

B. 28102

C. 29302

D. 26602

Simplification Questions Set 1 for IBPS Bank : Ques No 43

If 7 (3/6) of 534 + 262 = 61800 – x, then the value of x is

Options:

A. 56533

B. 57533

C. 58533

D. 37355

Simplification Questions Set 1 for RRB : Ques No 44

If 72% of 486 – 64% of 261 = k, then the value of k is

Options:

A. 184.66

B. 183.66

C. 188.88

D. 182.88

Simplification Questions Set 1 for SSC CGL : Ques No 45

If x ÷ 62 × 12 = 264, then the value of x is

Options:

A. 1364

B. 1284

C. 1348

D. 1388

Simplification Questions Set 1 for SSC CHSL : Ques No 46

If (53)² + (21)² = (x)² + 157, then the value of x is

Options:

A. 56.628

B. 55.614

C. 53.264

D. 58.814

Simplification Questions Set 1 for IBPS Bank : Ques No 47

If 65 % of 862 + x = 969, then the value of x is

Options:

A. 406.7

B. 408.7

C. 404.4

D. 405.8

Simplification Questions Set 1 for RRB : Ques No 48

If √(6084) = x, then the value of x is

Options:

A. 72

B. 82

C. 78

D. 88

Simplification Questions Set 1 for SSC CGL : Ques No 49

If 18.88 + 88.81 + 881.828 = x, then the value of x is

Options:

A. 981.518

B. 989.518

C. 969.518

D. 935.518

Simplification Questions Set 1 for SSC CHSL : Ques No 50

If [(78 – 32)2 / 23] + (2/5) of (16020/120) = x, then the value of x is

Options:

A. 316.9

B. 317.9

C. 318.9

D. 315.9

# Simplification Questions Set 1 Solutions

p = (5 / 6) × [(2 / 9) ÷ (4 / 9)] ÷ (6 / 7) = (5 / 6) × [ 1 / 2 ] × (7 / 6) = (35 / 72) = 0.486 ≈ 0.49

k = [(15 × 62.5) / 100] + [(10 × 4.80) / 100] = 9.375 + 0.48 = 9.855 ≈ 10

543.28 / 55 = 9.8778 ≈ 10

m = (33 / 0.16) × [5 / (28 × 7)] = (165 / 31.36) = 5.26 ≈ 5

x = 1.21 + 10.24 + 9 = 20.45 ≈ 20

y = (7895641 ÷ 2795 ÷ 123) × 345 ÷ 456 ≈ 23 × 0.75 ≈ 17

a = 3945 + 150 × 40 – 35.5 = 9945 – 35.5 = 9909.5 ≈ 9900

(63)2 × 3.545 = 3969 × 3.545 = 14070.10 ≈ 14070

x = 3.5 × 0.07 ÷ (1.7)2 = 3.5 × 0.07 ÷ 2.89 = 3.5 × 0.024 = 0.084 ≈ 1

k = 64% of 159.96 + 72% of 65.005 + (1.4)2 – (0.4)2 ≈ 64% of 160 + 72% of 65 + (1.4)2 – (0.4)2 ≈ 102.4 + 46.8 + 1.96 – 0.16 ≈ 151 .16 – 0.16 = 151

2567 ÷ 17 × 3 = x + 180 ⇒ 151 × 3 = x + 180 ⇒ 453 = x + 180 ⇒ x = 453 – 180 = 273

k = 7.5% of 140 + 2.5% of 80 = (75×140 / 10×100) + (25×80 / 10×100) = 10.5 + 2 = 12.5

b = 3/5 of 4/7 of 7/12 of 1375 = = 275

32.05 x 15 + d = 500 ⇒ d = 500 – 480.75 ⇒ d = 19.25

107.5 × 52.5 × 22.5 = 10x ⇒ 107.5 × 102.5 = 10x ⇒ 107.5 + 2.5 = 10x ⇒ 1010 = 10x ⇒ x = 10

k = 1 (8/9) + 3 (2/7) – 2 (1/7) + 11 (1/6) = (1+3+11-2) + [(8/9) + (2/7) + (1/6) – (1/7)] = 13 + [(8/9) + (1/7) + (1/6)] = 14 (25/126)

56%958 + 67% of 1008 = 536.48 + 675.36 = 1211.84. Now, 1211.84 = p% of 2000  p = 60.592

72.3 × 494.7 × 633.4 × 815.85 = 72.3 × 74.7 × 74.7 × 633.4 × 95.85 × 95.85 = 7(2.3+4.7+4.7) × 9(5.85+5.85) × 633.4 = 6311.7 × 633.4 = 6315.1. Thus, k = 15.1

(x)²+ (164)² = (307)² – 272 ⇒ (x)² = (307)² – 272 – (164)² ⇒ (x)² = 94249 – 272 – 26896 = 67081
Thus, x = √(67081) = 259

√(915849) + √(795664) = 957 + 892 = 1849  (x)² = 1849 ⇒ x = 43

6399 × (13 / 8) + 353 ÷ x = 10444  6400 ×(13 / 8) + (353 / x) ≈ 10444 ⇒ 800 × 13 + (353 / x) ≈ 10444 ⇒ (353 / x) = 10444 – 10400 ≈ 44 ⇒ x = 353 / 44 = 8.022 ≈ 8

x = √625 ×14 + √400 × 16 = 25 × 14 + 20 × 16 = 350 + 320 = 670

k = 8460 ÷ 12 – 24 × (100 / 5) = 705 – 24 × 20 = 705 – 480 = 225

p = [(14.85 × 679) / 100] + [(19.9 × 219.83) / 100] ≈ [(15 × 680) / 100] + [(20 × 220) / 100] = 102 + 44 = 146 ≈ 145

1441 ÷ k + 149.98 × 14.99 = 3006 – 254.91
≈ 1441 / k + 150 x 15 = 3006 – 255 ⇒ 1441 / k = 2751 – 2250 ⇒ 1441 / k = 501 ⇒ k = 1441 / 501 = 2.88 ≈ 3

8(1 / 2) + 4(2 / 7) = 5(1 / 2) + x ⇒ x = 8(1 / 2) + 4(2 / 7) – 5(1 / 2) = (8 + 4 – 5) + (1 / 2) + (2 / 7) – (1 / 2) = 7 + [(7 + 4 – 7) / 14] = 7 + (4 / 14) = 7(2 / 7)

x = 376 – 58.4 × 1.5 × 2.2 = 376 – 192.72 = 183.28

(p × 4680) / 100 = 1183.4 – [(46 × 1250) / 100] = 1183.4 – 575 = 608.4 ⇒ p = (608.4 × 100) / 4680 = 13

√x + 9.5 = √2916 – √1681 = 54 – 41 = 13 ⇒ √x = 13 – 9.5 = 3.5 ⇒ x = 3.5 × 3.5 = 12.25

x = 4642 + 2368 + 196 – 5986 = 7206 – 5986 = 1220

d = 9.5 ÷ 1.9 × 2.6 + 3.8 ÷ 1.9 × 2.5 = 5 × 2.6 + 2 × 2.5 = 13 + 5 = 18

d = 5.4 × 3.2 × 6.2 × (1.5)2 = 17.28 × 6.2 × 2.25 = 241.056

k = (54 / 100) × 680 + (24 / 100) × 280 – (12 / 100) × 120 = 367.2 + 67.2 – 14.4 = 420

[(x × 2150) / 100] = [(78 × 625) / 100] + [(35 × 450) / 100] = 487.50 + 157.5 = 645 ⇒ x = [(645 × 100) / 2150] = 30

x = (4 + 5 + 6 – 9) + [(5 / 2) + (4 / 2) + (3 / 2) – (1 / 2)] = 6 + [(5 + 4 + 3 – 1) / 2] = 6 + (11 / 2) = (6 + 5) + (1 / 2) = 11 (1 / 2)

3√13824 + √1849 = 3√9261 + √x ⇒ 24 + 43 = 21 + √x ⇒ √x = 67 – 21 = 46 ⇒ x = 2116

(0.8) ÷ (0.2)2 × (0.6)2 = (2.4)2 × k  5.76 × k = (0.8 / 0.04) × 0.36 = 20 × 0.36 = 7.20 ⇒ k = (7.20 / 5.76) = 1.25

x = 7654.32 + 8962.81 + 3432.12 – 512.32 + 212.82 + 316.84 = 20066.59

812 + 912 + 516 + 241 + 346 + 329 = 12 × k  3156 = 12 × k  k = (3156 / 12) = 263

p = 4√1296 + 4√2401 + 4√6561 – 4√256  p = 6 + 7 + 9 – 4 = 18

k = 2(1/6) + 2(1/2) = 4 + [(1+3)/6] = 4 + (2/3) = 4(2/3)

36251 + 43261 = x + 52310 ⇒ x = 36251 + 43261 – 52310 = 27202

(45/6) of 534 + 262 = 61800 – x ⇒ 45 × 89 + 262 = 61800 – x  61800 – 4267 = 57533

k = [((72×486)/100) – ((64×261)/100)] = 349.92 – 167.04 = 182.88

x = (264/12) × 62 = 1364

(x)² = (53)² + (21)² – 157 = 2809 + 441 – 157 = 3093 ⇒ (x) = √(3093) = 55.614

x = 969 – [(862×65)/100] = 969 – 560.3 = 408.7