Hi students, Welcome to Amans Maths Blogs (AMBIPi). Are you preparing for SSC CHSL Exam and looking for SSC CHSL Exam Math Number System Question with Solutions AMBIPi? In this article, you will get Previous Year Mathematics Questions asked in SSC CHSL, which helps you in the preparation of government job exams of SSC CHSL.
SSC CHSL Exam Math Number System Question with Solutions
SSC CHSL Exam Math Question: 1
The greatest value among the fractions 2/7 , 1/3, 5/6, 3/4 is
Option A : 3/4
Option B : 5/6
Option C : 1/3
Option D : 2/7
Show/Hide Answer Key
Option B : 5/6
2/7 = 0.286 ; 1/3 = 0.33
5/6 = 0.833 ; 3/4 = 0.75
SSC CHSL Previous Year Math Questions: 2
If a number is as much greater than 31 as it is less than 75, then the number is
Option A : 106
Option B : 44
Option C : 74
Option D : 53
Show/Hide Answer Key
Option D : 53
If the number be x, then
x -31 = 75 – x
2x = 75 + 31 = 106
x = 53
SSC CHSL Previous Year Math Paper: 3
Arrangement of the fractions 4/3, – 2/9, – 7/8, 5/12 into ascending order
Option A : -7/8 , -2/9, 5/12, 4/3
Option B : – 7/8 , -2/9, 4/3 , 5/12
Option C : -2/9 , -7/8, 5/12, 4/3
Option D : -2/9 , -7/8, 4/3 , 5/12
Show/Hide Answer Key
Option A : -7/8 , -2/9, 5/12, 4/3
Decimal equivalents of fractions :
4/3 = 1.3
– 2.9 = 0.2
– 7/8 = -0.875
5/12 = 0.42
– 0.875 < – 0.2 < 0.42 < 1.3
i.e -7/8 , -2/9, 5/12, 4/3
SSC CHSL Mock Test Math Question: 4
Which of the following numbers will always divide a six digit number of the form xyxyxy (where 1< x < 9 < 1< y < 9)?
Option A : 1010
Option B : 10101
Option C : 11011
Option D : 11010
Show/Hide Answer Key
Option B : 10101
Number = xy xy xy
= xy × 10000 + xy × 100 + xy
= xy (10000 + 100 + 1)
= xy × 10101
SSC CHSL Free Mock Test Math Question: 5
When a number is divided by 387, the remainder obtained is 48. If the same number is divided by 43, then the remainder obtained will be–
Option A : 0
Option B : 3
Option C : 5
Option D : 35
Show/Hide Answer Key
Option C: 5
SSC CHSL Advance Math Question: 6
When two numbers are separately divided by 33, the remainders are 21 and 28 respectively. If the sum of the two numbers is divided by 33, the remainder will be
Option A : 10
Option B : 12
Option C : 14
Option D : 16
Show/Hide Answer Key
Option D : 16
If two numbers are separately divided by a certain divisor (d)leaving remainders r1 and r2 then remainder after their sum is divided by the same divisor.
r1 + r2 – d
21 + 28 – 33 = 16
SSC CHSL Math Previous Year Question: 7
The expression 26n – 42n, wheren is a natural number is always divisible by
Option A : 15
Option B : 18
Option C : 36
Option D : 48
Show/Hide Answer Key
Option D : 48
64 –16= 48
SSC CHSL Math Question Paper: 8
47 is added to the product of 71 and an unknown number. The new number is divisible by 7 giving the quotient 98. The unknown number is a multiple of
Option A : 2
Option B : 5
Option C : 7
Option D : 3
Show/Hide Answer Key
Option D : 3
Let the unknown number bex.
71x x + 47 = 98x 7
= 71 x = 686 – 47 = 639
x = 639/71 = 9 = 3×3
Advance Math Question Asked in SSC CHSL: 9
When an integer K is divided by 3, the remainder is 1, and when K + 1 is divided by 5, the remainder is 0. Of the following, a possible value of K is:
Option A : 62
Option B : 63
Option C : 64
Option D : 65
Show/Hide Answer Key
Option C : 64
Of the given alternatives,
When 64 is divided by 3, remainder = 1
When 65 is divided by 5, remainder = 0
Previous Year Math Question Paper SSC CHSL: 10
A number when divided by 91 gives a remainder 17. When the same number is divided by 13, the remainder will be :
Option A : 0
Option B : 4
Option C : 6
Option D : 3
Show/Hide Answer Key
Option B : 4
Here, the first divisor (91) is a multiple of second divisor (13).
Required remainder = Remainder obtained on dividing 17
by 13 = 4
SSC CHSL Exam Math Number System Question: 11
If the sum of the two numbers is 120 and their quotient is 5, then the difference of the two numbers is–
Option A : 115
Option B : 100
Option C : 80
Option D : 72
Show/Hide Answer Key
Option C : 80
Difference = 100 – 20 = 80
SSC CHSL Previous Year Math Number System Questions: 12
A number when divided by 280 leaves 115 as remainder. When the same number is divided by 35, the remainder is
Option A : 15
Option B : 10
Option C : 20
Option D : 17
Show/Hide Answer Key
Option B : 10
Here, 280 is a multiple of 35.
Required remainder
= Remainder obtained on dividing 115 by 35 = 10
SSC CHSL Previous Year Math Number System Paper: 13
A certain number when divided by 175 leaves a remainder 132. When the same number is divided by 25, the remainder is
Option A : 6
Option B : 7
Option C : 8
Option D : 9
Show/Hide Answer Key
Option B : 7
Here, first divisor (175) is a multiple of second divisor (25).
Required remainder = Remainder obtained on dividing 132 by
25 = 7
SSC CHSL Mock Test Math Number System Question: 14
When n is divided by 6, the remainder is 4. When 2n is divided by 6, the remainder is
Option A : 2
Option B : 0
Option C : 4
Option D : 1
Show/Hide Answer Key
Option A : 2
n = 6q + 4
2n = 12q + 8
Dividing 8 by 6 the remainder = 2
SSC CHSL Free Mock Test Math Number System Question: 15
Two numbers 11284 and 7655, when divided by a certain number of three digits, leaves the same remainder. The sum of digits of such a three digit number is
Option A : 8
Option B : 9
Option C : 10
Option D : 11
Show/Hide Answer Key
Option D : 11
3629 = 19 × 191
Hence, required number = 191
Sum of digits = 1 + 9 + 1 = 11
SSC Advance Math Number System Question: 16
In a division sum, the divisor is 3 times the quotient and 6 times the remainder. If the remainder is 2, then the dividend is
Option A : 50
Option B : 48
Option C : 36
Option D : 28
Show/Hide Answer Key
Option A : 50
Dividend = 12 × 4 + 2
= 48 + 2 = 50
SSC CHSL Math Previous Year Number System Question: 17
If the sum of the digits of any integer lying between 100 and 1000 is subtracted from the number, the result always is
Option A : divisible by 6
Option B : divisible by 2
Option C : divisible by 9
Option D : divisible by 5
Show/Hide Answer Key
Option C : divisible by 9
Number = 100x + 10y + z
Sum of digits = x + y + z
Difference = 100x + 10y + z – x –
y – z
= 99x + 9y = 9 (11x + y)
SSC CHSL Math Number System Question Paper: 18
5349 is added to 3957. Then 7062 is subtracted from the sum. The result is not divisible by
Option A : 4
Option B : 3
Option C : 7
Option D : 11
Show/Hide Answer Key
Option D : 11
Advance Math Number System Question Asked in SSC CHSL: 19
The product of all the prime numbers between 80 and 90 is
Option A : 83
Option B : 89
Option C : 7387
Option D : 598347
Show/Hide Answer Key
Option C : 7387
Prime numbers between 80
and 90.
= 83 and 89
Required product = 83 × 89
= 7387
Previous Year Math Number System Question Paper SSC CHSL: 20
If n is even, (6n– 1) is divisible by
Option A : 37
Option B : 35
Option C : 30
Option D : 6
Show/Hide Answer Key
Option B : 35
