Hi students, Welcome to Amans Maths Blogs (AMBIPi). Are you preparing for SSC CGL Tier 1 and 2 and looking for SSC CGL Exam Free Mock Test Math Number System Question with Solutions AMBIPi? In this article, you will get Previous Year Mathematics Questions asked in SSC CGL Tier 1 and Tier 2, which helps you in the preparation of government job exams of SSC CGL.
SSC CGL Exam Math Number System Question with Solutions
SSC CGL Exam Math Question: 1
The least number, which is to be added to the greatest number of 4 digits so that the sum may be divisible by 345, is
Option A : 50
Option B : 6
Option C : 60
Option D : 5
Show/Hide Answer Key
Option B : 6
The largest 4-digit number= 9999
Required number = 345 – 339= 6
SSC CGL Previous Year Math Questions: 2
The difference of a number consisting of two digits from the number formed by interchanging the digits is always divisible by
Option A : 10
Option B : 9
Option C : 11
Option D : 6
Show/Hide Answer Key
Option B : 9
Let the number be 10x + y where y < x.
Number obtained by interchanging the digits = 10y + x
Difference = 10x + y – 10y – x= 9x – 9y = 9 (x – y)
Hence, the difference is always exactly divisible by 9.
SSC CGL Previous Year Math Paper: 3
Which one of the numbers is di-visible by 25 ?
Option A : 303310
Option B : 373355
Option C : 303375
Option D : 22040
Show/Hide Answer Key
Option C : 303375
SSC CGL Mock Test Math Question: 4
The least number which must be added to the greatest number of 4 digits in order that the sum may be exactly divisible by 307 is
Option A : 132
Option B : 32
Option C : 43
Option D : 75
Show/Hide Answer Key
Option A : 132
307 × 32 = 9824
307 × 33 = 10131
Required number= 10131 – 9999 = 132
SSC CGL Free Mock Test Math Question: 5
If a = 4011 and b = 3989 then value of ab = ?
Option A : 15999879
Option B : 15899879
Option C : 15989979
Option D : 15998879
Show/Hide Answer Key
Option A : 15999879
a = 4011, b = 3989
ab = 4011 × 3989= (4000 + 11) (4000 – 11)= (4000)2 – (11)2 = 16000000 – 121 = 15999879
SSC CGL Advance Math Question: 6
For any integral value of n, 32n+ 9n + 5 when divided by 3 will leave the remainder
Option A : 1
Option B : 2
Option C : 0
Option D : 5
Show/Hide Answer Key
Option B : 2
SSC CGL Math Previous Year Question: 7
In a farm there are cows and hens. If heads are counted they are 180, if legs are counted they are 420. The number of cows in the farm is
Option A : 130
Option B : 150
Option C : 50
Option D : 30
Show/Hide Answer Key
Option D : 30
A cow and a hen each has a head.
If the total number of cows be x, then
Number of hens = 180 – x A cow has four legs and a hence
has two legs.
(180 – x) × 2 + 4x = 420
Þ 360 – 2x + 4x = 420
Þ 2x = 420 – 360 = 60 Þ x =602= 30
SSC CGL Math Question Paper: 8
The number which can be writ- ten in the form of n (n + 1) (n + 2), where n is a natural number, is
Option A : 7
Option B : 3
Option C : 5
Option D : 6
Show/Hide Answer Key
Option D : 6
On putting n = 1 n(n +1) (n + 2) = 1 × 2 × 3 = 6
Advance Math Question Asked in SSC CGL: 9
A number when divided by 2736 leaves the remainder 75. If the same number is divided by 24, then the remainder is
Option A : 12
Option B : 3
Option C : 0
Option D : 23
Show/Hide Answer Key
Option D : 23
2736 ÷ 24 = 114
Hence, first divisor (2736) is a
multiple of second divisor (24).
Required remainder = Remainder obtained on
dividing 75 by 24 = 3
Previous Year Math Question Paper SSC CGL: 10
The sum of four numbers is 48. When 5 and 1 are added to the first two; and 3 and 7 are sub- tracted from the 3rd and 4th, the numbers will be equal. The numbers are
Option A : 9, 7, 15, 17
Option B : 4, 12, 12, 20
Option C : 5, 11, 13, 19
Option D : 16, 10, 14, 18
Show/Hide Answer Key
Option D : 16, 10, 14, 18
SSC CGL Exam Math Number System Question: 11
The least number that should be added to 2055, so that the sum is exactly divisible by 27 is
Option A : 28
Option B : 24
Option C : 27
Option D : 31
Show/Hide Answer Key
Option B : 24
Required number = 27 – 3 = 24
SSC CGL Previous Year Math Number System Questions: 12
A number when divided by 361 gives a remainder 47. If the same number is divided by 19, the re- mainder obtained is
Option A : 3
Option B : 8
Option C : 9
Option D : 1
Show/Hide Answer Key
Option C : 9
Here, the first divisor (361) is a multiple of second divisor (19).
Required remainder = Remainder obtained on dividing 47 by 19 = 9
SSC CGL Previous Year Math Number System Paper: 13
Which one of the following is the minimum value of the sum of two integers whose product is 24?
Option A : 25
Option B : 11
Option C : 8
Option D : 10
Show/Hide Answer Key
Option D : 10
xy = 24
(x, y)= (1 × 24), (2 ×12), (3 × 8), (4 × 6)
Minimum value of (x + y)= 4 + 6 = 10.
SSC CGL Mock Test Math Number System Question: 14
If the sum of the digits of a three digit number is subtracted from that number, then it will always be divisible by
Option A : 3 only
Option B : 9 only
Option C : Both 3 and 9 only
Option D : All of 3, 6 and 9
Show/Hide Answer Key
Option C : Both 3 and 9 only
Let the 3–digit number be
100x + 10y + z.
Sum of the digits = x + y + z
According to the question,
Difference= 100x + 10y + z – (x + y + z)= 99x + 9y= 9 (11x + y)
Clearly, it is a multiple of 3 and9.
SSC CGL Free Mock Test Math Number System Question: 15
The greater of the two numbers whose product is 900 and sum exceeds their difference by 30 is
Option A : 60
Option B : 75
Option C : 90
Option D : 100
Show/Hide Answer Key
Option A : 60
SSC CGL Advance Math Number System Question: 16
In a division sum, the divisor ‘d’ is 10 times the quotient ‘q’ and 5 times the remainder ‘r’. If r = 46, the dividend will be
Option A : 5042
Option B : 5328
Option C : 5336
Option D : 4276
Show/Hide Answer Key
Option C : 5336
According to the question,
Divisor (d) = 5r = 5 × 46 = 230
Again, Divisor (d) = 10 × Quotient (q)
Þ 230 = q × 10
Þ q =23010 = 23
\ Dividend = Divisor × Quotient+ Remainder= 230 × 23 + 46= 5290 + 46 = 5336
SSC CGL Math Previous Year Number System Question: 17
If the sum of a number and its reciprocal be 2, then the number is
Option A : 0
Option B : 1
Option C : -1
Option D : 2
Show/Hide Answer Key
Option B : 1
SSC CGL Math Number System Question Paper: 18
When a number is divided by 56, the remainder will be 29. If the same number is divided by 8, then the remainder will be
Option A : 6
Option B : 7
Option C : 5
Option D : 3
Show/Hide Answer Key
Option C : 5
First divisor (56) is a mul-tiple of second divisor (8).Required remainder= Remainder obtained after dividing 29 by 8 = 5
Advance Math Number System Question Asked in SSC CGL: 19
A positive number when de-creased by 4, is equal to 21 times the reciprocal of this number. The number is :
Option A : 3
Option B : 7
Option C : 5
Option D : 9
Show/Hide Answer Key
Option B : 7
Previous Year Math Number System Question Paper SSC CGL: 20
When n is divided by 4, the remainder is 3. The remainder when 2n is divided by 4 is
Option A : 1
Option B : 2
Option C : 3
Option D : 6
Show/Hide Answer Key
Option D : 2
Let quotient be 1.n = 4 × 1 + 3 = 7
2n = 2 × 7 = 14,On dividing 14 by 4, remainder= 2
