SI and CI Questions Set 1 | for SSC CGL | SSC CHSL | IBPS | RRB
There are following SI and CI Questions Set 1 for SSC CGL, SSC CHSL, IBPS Bank, RRB. The answer with the solutions of these SI and CI questions is at last. This post contains combined questions of SI and CI. The questions are based on both SI and CI concepts. So for this you need to learn the SI and CI formulas short tips and tricks.
SI and CI Questions Set 1 for SSC CGL : Question No 1
If the compound interest on a certain sum for 2 years at 3% per annum is 101.50, then the simple interest on the same sum at the same rate and for the same time will be
Options:
A. Rs. 90
B. Rs. 95.50
C. Rs. 100
D. Rs. 98.25
SI and CI Questions Set 1 for SSC CHSL : Question No 2
If the compound interest on a sum of money for 3 years at the rate of 5% per annum is Rs. 252.20, the simple interest on the same sum at the same rate and for the same time is
Options:
A. Rs. 220
B. Rs. 240
C. Rs. 245
D. Rs. 250
SI and CI Questions Set 1 for IBPS Bank : Question No 3
On a certain sum of money the compound interest for 2 years is Rs. 282.15 and the simple interest
for the same period of time is Rs. 270. The rate of interest per annum is
Options:
A. 6.07%
B. 10%
C. 9%
D. 12.15%
SI and CI Questions Set 1 for RRB : Question No 4
If the compound interest on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the simple interest on the same sum at the same rate for the same period of time is :
Options:
A. Rs. 400
B. Rs. 480
C. Rs. 450
D. Rs. 460
SI and CI Questions Set 1 for SSC CGL : Question No 5
The compound interest on a certain sum of money at a certain rate for 2 years is Rs. 40.80 and the simple interest on the same sum is 40 at the same rate and for the same time. The rate of interest is
Options:
A. 2% per annum
B. 3% per annum
C. 4% per annum
D. 5% per annum
SI and CI Questions Set 1 for SSC CHSL : Question No 6
The compound interest on a certain sum of money invested for 2 years at 5% per annum is Rs. 328. The simple interest on the sum, at the same rate and for the same period will be
Options:
A. Rs. 320
B. Rs. 308
C. Rs. 300
D. Rs. 287
SI and CI Questions Set 1 for IBPS Bank : Question No 7
Compound interest on a sum of money for 2 years at 4 per cent per annum is Rs. 2448. Simple interest of the same sum of money at the same rate of interest for 2 years will be
Options:
A. Rs. 2500
B. Rs. 2400
C. Rs. 2360
D. Rs. 2250
SI and CI Questions Set 1 for RRB : Question No 8
At a certain rate per annum, the simple interest on a sum of money for one year is 260 and the compound interest on the same sum for two years is Rs. 540.80. The rate of interest per annum is
Options:
A. 4%
B. 6%
C. 8%
D. 10%
SI and CI Questions Set 1 for SSC CGL : Question No 9
The simple interest on a sum of money at 4% per annum for 2 years is 80. The compound interest in the same sum for the same period is
Options:
A. Rs. 82.60
B. Rs. 82.20
C. Rs. 81.80
D. Rs. 81.60
SI and CI Questions Set 1 for SSC CHSL : Question No 10
The compound interest on a certain sum of money at 5% per annum for 2 years is 246. The simple interest on the same sum for 3 years at 6% per annum is
Options:
A. Rs. 435
B. Rs. 450
C. Rs. 430
D. Rs. 432
SI and CI Questions Set 1 for IBPS Bank : Question No 11
The simple interest and compound interest (compounded annually) on a certain sum of money with a given rate for a period of 2 years are Rs. 900 and Rs. 954 respectively. The sum of money is
Options:
A. Rs. 3700
B. Rs. 3650
C. Rs. 3850
D. Rs. 3750
SI and CI Questions Set 1 for RRB : Question No 12
The compound interest on a certain sum of money for 2 years at 10% per annum is 420. The simple interest on the same sum at the same rate and for the same time will be
Options:
A. Rs. 350
B. Rs. 375
C. Rs. 380
D. Rs. 400
SI and CI Questions Set 1 for SSC CGL : Question No 13
If the compound interest on a certain sum for 2 years at 4% p.a. is 102, the simple interest at the same rate of interest for two years would be
Options:
A. Rs. 200
B. Rs. 50
C. Rs. 150
D. Rs. 100
SI and CI Questions Set 1 for SSC CHSL : Question No 14
There is 100% increase to an amount in 8 years, at simple interest. Find the compound interest of 8000 after 2 years at the same rate of interest
Options:
A. Rs. 2500
B. Rs. 2000
C. Rs. 2250
D. Rs. 2125
SI and CI Questions Set 1 for IBPS Bank : Question No 15
If the compound interest on a certain sum for two years at 12% per annum is 2,544, the simple interest on it at the same rate for 2 years will be
Options:
A. Rs. 2400
B. Rs. 2500
C. Rs. 2480
D. Rs. 2440
SI and CI Questions Set 1 Solutions
Answer 1 : C
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 101.50, R = 3%, SI = ?, then
101.50 = SI(1 + 3/200)
101.50 = SI(203/200)
SI = (101.50 x 200) / 203
SI = Rs. 100
Answer 2 : B
P = ?, CI = 252.20, R = 5%, n = 3 years
CI = P[(1 + R/100)^n – 1]
252.20 = P[(1 + 5/100)^3 – 1]
252.20 = P[(1 + 1/20)^3 – 1]
252.20 = P[(21/20)^3 – 1]
252.20 = P[(9261/8000) – 1]
252.20 = P x (1261/8000)
P = (252.20 x 8000) / 1261
P = 1600
Thus,
SI = PRT / 100
SI = (1600 x 5 x 3) / 100
SI = Rs. 240
Answer 3 : C
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then
CI = SI(1 + R/200)
Since CI = 282.15, R = ?, SI = 270, then
282.15 = 270(1 + R/200)
282.15 / 270 = (1 + R/200)
(282.15 / 270) – 1 = R/200
12.15 / 270 = R/200
R = (12.15 x 200) / 270
R = 9%
Answer 4 : B
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 510, R = 12 1/2% = 25/2%, SI = ?, then
510 = SI(1 + 25/400)
510 = SI x 425/400
SI = (510 x 400) / 425
SI = Rs. 480
Answer 5 : C
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 40.80, R = ?, SI = 40, then
40.80 = 40(1 + R/200)
40.80/40 = 1 + R/200
4080/4000 = 1 + R/200
408/400 = (200 + R)/200
(408/400) x 200 = 200 + R
204 = 200 + R
R = 4% per annum
Answer 6 : A
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 328, R = 5%, SI = ?, then
328 = SI(1 + 5/200)
328 = SI(1 + 1/40)
328 = SI(41/40)
SI = (328 x 40) / 41
SI = Rs. 320
Answer 7 : B
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 2448, R = 4%, SI = ?, then
2448 = SI(1 + 4/200)
2448 = SI(204/200)
SI = (2448 x 200) / 204
SI = Rs. 2400
Answer 8 : C
SI = PRT/100 = PR x 1/100 = 260,
Thus PR = 26000
Now, CI = 540.80, n = 2 years
540.80 = P[(1 + R/100)^2 – 1]
540.80 = P[1 + (R/100)^2 + 2(R/100) – 1]
540.80 = P[(R/100)^2 + 2(R/100)]
540.80 = (PR)R/10000 + 2(PR/100)
Since PR = 26000
540.80 = 26000R/10000 + 2(26000/100)
540.80 = 26R/10 + 520
540.80 – 520 = 26R/10
20.80 x 10 = 26R
R = 208/26 = 8%
Answer 9 : D
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = ?, R = 4%, SI = 80, then
CI = 80(1 + 4/200)
CI = 80(1 + 1/50)
CI = (80 x 51) / 50
CI = Rs. 81.60
Answer 10 : D
P = ?, CI = 246, R = 5%, n = 2 years
CI = P[(1 + R/100)^n – 1]
246 = P[(1 + 5/100)^2 – 1]
246 = P[(1 + 1/20)^2 – 1]
246 = P[(21/20)^2 – 1]
246 = P[(441/400) – 1]
246 = P x (41/400)
P = (246 x 400) / 41
P = 2400
Thus,
SI = PRT / 100
SI = (2400 x 6 x 3) / 100
SI = Rs. 432
Answer 11 : D
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 954, R = ?, SI = 900, then
954 = 900(1 + R/200)
954/900 = 1 + R/200
954/900 – 1 = R/200
54/900 = R/200
R = 12%
Thus,
SI = PRT / 100
900 = (P x 12 x 2) / 100
P = Rs. 3750
Answer 12 : D
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 420, R = 10%, SI = ?, then
420 = SI(1 + 10/200)
420 = SI(1 + 1/20)
420 = SI(21/20)
SI = (420 x 20) / 21
SI = Rs. 400
Answer 13 : D
P = ?, CI = 102, R = 4%, n = 2 years
CI = P[(1 + R/100)^n – 1]
102 = P[(1 + 4/100)^2 – 1]
102 = P[(1 + 1/25)^2 – 1]
102 = P[(26/25)^2 – 1]
102 = P[(676/625) – 1]
102 = P x (51/625)
P = (102 x 625) / 21
P = 1250
Thus,
SI = PRT / 100
SI = (1250 x 2 x 4) / 100
SI = Rs. 100
Answer 14 : D
P = 100, SI = 100, R = ?, n = 8 years
SI = PRT / 100
100 = (100 x R x 8) / 100
R = 100 / 8 = 25/2%
Now, P = 8000, CI = ?, R = 25/2, n = 2 years
CI = P[(1 + R/100)^n – 1]
CI = 8000[(1 + 25/200)^2 – 1]
CI = 8000[(1 + 1/8)^2 – 1]
CI = 8000[(9/8)^2 – 1]
CI = 8000[(81/64) – 1]
CI = 8000 x 17 / 64
CI = Rs. 2125
Answer 15 : A
The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is
CI = SI(1 + R/200)
Since CI = 2544, R = 12%, SI = ?, then
2544 = SI(1 + 12/200)
2544 = SI(212/200)
SI = (2544 x 200) / 212
SI = Rs. 2400
