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# SI and CI Questions Set 1 | for SSC CGL | SSC CHSL | IBPS | RRB

There are following SI and CI Questions Set 1 for SSC CGL, SSC CHSL, IBPS Bank, RRB. The answer with the solutions of these SI and CI questions is at last. This post contains combined questions of SI and CI. The questions are based on both SI and CI concepts. So for this you need to learn the SI and CI formulas short tips and tricks.

SI and CI Questions Set 1 for SSC CGL : Question No 1

If the compound interest on a certain sum for 2 years at 3% per annum is 101.50, then the simple interest on the same sum at the same rate and for the same time will be

Options:

A. Rs. 90

B. Rs. 95.50

C. Rs. 100

D. Rs. 98.25

SI and CI Questions Set 1 for SSC CHSL : Question No 2

If the compound interest on a sum of money for 3 years at the rate of 5% per annum is Rs. 252.20, the simple interest on the same sum at the same rate and for the same time is

Options:

A. Rs. 220

B. Rs. 240

C. Rs. 245

D. Rs. 250

SI and CI Questions Set 1 for IBPS Bank : Question No 3

On a certain sum of money the compound interest for 2 years is Rs. 282.15 and the simple interest
for the same period of time is Rs. 270. The rate of interest per annum is

Options:

A. 6.07%

B. 10%

C. 9%

D. 12.15%

SI and CI Questions Set 1 for RRB : Question No 4

If the compound interest on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the simple interest on the same sum at the same rate for the same period of time is :

Options:

A. Rs. 400

B. Rs. 480

C. Rs. 450

D. Rs. 460

SI and CI Questions Set 1 for SSC CGL : Question No 5

The compound interest on a certain sum of money at a certain rate for 2 years is Rs. 40.80 and the simple interest on the same sum is 40 at the same rate and for the same time. The rate of interest is

Options:

A. 2% per annum

B. 3% per annum

C. 4% per annum

D. 5% per annum

SI and CI Questions Set 1 for SSC CHSL : Question No 6

The compound interest on a certain sum of money invested for 2 years at 5% per annum is Rs. 328. The simple interest on the sum, at the same rate and for the same period will be

Options:

A. Rs. 320

B. Rs. 308

C. Rs. 300

D. Rs. 287

SI and CI Questions Set 1 for IBPS Bank : Question No 7

Compound interest on a sum of money for 2 years at 4 per cent per annum is Rs. 2448. Simple interest of the same sum of money at the same rate of interest for 2 years will be

Options:

A. Rs. 2500

B. Rs. 2400

C. Rs. 2360

D. Rs. 2250

SI and CI Questions Set 1 for RRB : Question No 8

At a certain rate per annum, the simple interest on a sum of money for one year is 260 and the compound interest on the same sum for two years is Rs. 540.80. The rate of interest per annum is

Options:

A. 4%

B. 6%

C. 8%

D. 10%

SI and CI Questions Set 1 for SSC CGL : Question No 9

The simple interest on a sum of money at 4% per annum for 2 years is 80. The compound interest in the same sum for the same period is

Options:

A. Rs. 82.60

B. Rs. 82.20

C. Rs. 81.80

D. Rs. 81.60

SI and CI Questions Set 1 for SSC CHSL : Question No 10

The compound interest on a certain sum of money at 5% per annum for 2 years is 246. The simple interest on the same sum for 3 years at 6% per annum is

Options:

A. Rs. 435

B. Rs. 450

C. Rs. 430

D. Rs. 432

SI and CI Questions Set 1 for IBPS Bank : Question No 11

The simple interest and compound interest (compounded annually) on a certain sum of money with a given rate for a period of 2 years are Rs. 900 and Rs. 954 respectively. The sum of money is

Options:

A. Rs. 3700

B. Rs. 3650

C. Rs. 3850

D. Rs. 3750

SI and CI Questions Set 1 for RRB : Question No 12

The compound interest on a certain sum of money for 2 years at 10% per annum is 420. The simple interest on the same sum at the same rate and for the same time will be

Options:

A. Rs. 350

B. Rs. 375

C. Rs. 380

D. Rs. 400

SI and CI Questions Set 1 for SSC CGL : Question No 13

If the compound interest on a certain sum for 2 years at 4% p.a. is 102, the simple interest at the same rate of interest for two years would be

Options:

A. Rs. 200

B. Rs. 50

C. Rs. 150

D. Rs. 100

SI and CI Questions Set 1 for SSC CHSL : Question No 14

There is 100% increase to an amount in 8 years, at simple interest. Find the compound interest of 8000 after 2 years at the same rate of interest

Options:

A. Rs. 2500

B. Rs. 2000

C. Rs. 2250

D. Rs. 2125

SI and CI Questions Set 1 for IBPS Bank : Question No 15

If the compound interest on a certain sum for two years at 12% per annum is 2,544, the simple interest on it at the same rate for 2 years will be

Options:

A. Rs. 2400

B. Rs. 2500

C. Rs. 2480

D. Rs. 2440

# SI and CI Questions Set 1 Solutions

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 101.50, R = 3%, SI = ?, then

101.50 = SI(1 + 3/200)

101.50 = SI(203/200)

SI = (101.50 x 200) / 203

SI = Rs. 100

P = ?, CI = 252.20, R = 5%, n = 3 years

CI = P[(1 + R/100)^n – 1]

252.20 = P[(1 + 5/100)^3 – 1]

252.20 = P[(1 + 1/20)^3 – 1]

252.20 = P[(21/20)^3 – 1]

252.20 = P[(9261/8000) – 1]

252.20 = P x (1261/8000)

P = (252.20 x 8000) / 1261

P = 1600

Thus,

SI = PRT / 100

SI = (1600 x 5 x 3) / 100

SI = Rs. 240

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then

CI = SI(1 + R/200)

Since CI = 282.15, R = ?, SI = 270, then

282.15 = 270(1 + R/200)

282.15 / 270 = (1 + R/200)

(282.15 / 270) – 1 = R/200

12.15 / 270 = R/200

R =  (12.15 x 200) / 270

R = 9%

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 510, R = 12 1/2% = 25/2%, SI = ?, then

510 = SI(1 + 25/400)

510 = SI x 425/400

SI = (510 x 400) / 425

SI = Rs. 480

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 40.80, R = ?, SI = 40, then

40.80 = 40(1 + R/200)

40.80/40 = 1 + R/200

4080/4000 = 1 + R/200

408/400 = (200 + R)/200

(408/400) x 200 = 200 + R

204 = 200 + R

R = 4% per annum

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 328, R = 5%, SI = ?, then

328 = SI(1 + 5/200)

328 = SI(1 + 1/40)

328 = SI(41/40)

SI = (328 x 40) / 41

SI = Rs. 320

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 2448, R = 4%, SI = ?, then

2448 = SI(1 + 4/200)

2448 = SI(204/200)

SI = (2448 x 200) / 204

SI = Rs. 2400

SI = PRT/100 = PR x 1/100 = 260,

Thus PR = 26000

Now, CI = 540.80, n = 2 years

540.80 = P[(1 + R/100)^2 – 1]

540.80 = P[1 + (R/100)^2 + 2(R/100) – 1]

540.80 = P[(R/100)^2 + 2(R/100)]

540.80 = (PR)R/10000 + 2(PR/100)

Since PR = 26000

540.80 = 26000R/10000 + 2(26000/100)

540.80 = 26R/10 + 520

540.80 – 520 = 26R/10

20.80 x 10 = 26R

R = 208/26 = 8%

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = ?, R = 4%, SI = 80, then

CI = 80(1 + 4/200)

CI = 80(1 + 1/50)

CI = (80 x 51) / 50

CI = Rs. 81.60

P = ?, CI = 246, R = 5%, n = 2 years

CI = P[(1 + R/100)^n – 1]

246 = P[(1 + 5/100)^2 – 1]

246 = P[(1 + 1/20)^2 – 1]

246 = P[(21/20)^2 – 1]

246 = P[(441/400) – 1]

246 = P x (41/400)

P = (246 x 400) / 41

P = 2400

Thus,

SI = PRT / 100

SI = (2400 x 6 x 3) / 100

SI = Rs. 432

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 954, R = ?, SI = 900, then

954 = 900(1 + R/200)

954/900 = 1 + R/200

954/900 – 1 = R/200

54/900 = R/200

R = 12%

Thus,

SI = PRT / 100

900 = (P x 12 x 2) / 100

P = Rs. 3750

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 420, R = 10%, SI = ?, then

420 = SI(1 + 10/200)

420 = SI(1 + 1/20)

420 = SI(21/20)

SI = (420 x 20) / 21

SI = Rs. 400

P = ?, CI = 102, R = 4%, n = 2 years

CI = P[(1 + R/100)^n – 1]

102 = P[(1 + 4/100)^2 – 1]

102 = P[(1 + 1/25)^2 – 1]

102 = P[(26/25)^2 – 1]

102 = P[(676/625) – 1]

102 = P x (51/625)

P = (102 x 625) / 21

P = 1250

Thus,

SI = PRT / 100

SI = (1250 x 2 x 4) / 100

SI = Rs. 100

P = 100, SI = 100, R = ?, n = 8 years

SI = PRT / 100

100 = (100 x R x 8) / 100

R = 100 / 8 = 25/2%

Now, P = 8000, CI = ?, R = 25/2, n = 2 years

CI = P[(1 + R/100)^n – 1]

CI = 8000[(1 + 25/200)^2 – 1]

CI = 8000[(1 + 1/8)^2 – 1]

CI = 8000[(9/8)^2 – 1]

CI = 8000[(81/64) – 1]

CI = 8000 x 17 / 64

CI = Rs. 2125

The simple interest for a certain sum for 2 years at an annual rate interest R% is SI, then the compound interest is

CI = SI(1 + R/200)

Since CI = 2544, R = 12%, SI = ?, then

2544 = SI(1 + 12/200)

2544 = SI(212/200)

SI = (2544 x 200) / 212

SI = Rs. 2400

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