# NCERT Solutions for Class 12 Maths Application of Derivatives

Hi Students, Welcome to **Amans Maths Blogs (AMB)**. In this post, you will get the * NCERT Solutions for Class 12 Maths Application of Derivative Exercise 6.4*.

* NCERT Solutions for Class 12 Maths* are not only the solutions of Maths exercise but it builds your foundation of other important subjects. Getting knowledge of depth concept of

*like Algebra, Calculus, Trigonometry, Coordinate Geometry help you to understand the concept of Physics and Physical Chemistry.*

**CBSE Class 12**^{th}MathsAs we know that all the schools affiliated from CBSE follow the NCERT books for all subjects. You can check the **CBSE NCERT Syllabus**. Thus, * NCERT Solutions* helps the students to solve the exercise questions as given in

*.*

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**NCERT solutions for class 12**.

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**NCERT Solutions for Class 12 Maths Application of Derivative Exercise 6.2*** CBSE Class 12^{th}* is an important school class in your life as you take some serious decision about your career. And out of all subjects, Maths is an important and core subjects. So

*is major role in your exam preparation as it has detailed chapter wise solutions for all exercise. This*

**CBSE NCERT Solutions for Class 12**^{th}Maths**can be downloaded in PDF file. The downloading link is given at last.**

*NCERT Solutions*## NCERT Solutions for Class 12 Maths Application of Derivatives Exercise 6.4

**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 1.**

Using differentials, find the approximate value of each of the following up to 3 places of decimal.

(i)

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(ii)

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(iii)

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(iv)

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(v)

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(vi)

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(vii)

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(viii)

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(ix)

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(x)

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(xi)

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(xii)

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(xiii)

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(xiv)

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(xv)

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 2.**

Find the approximate value of f(2.01), where f(x) = 4x^{2} + 5x + 2.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 3.**

Find the approximate value of f (5.001), where f (x) = x^{3} – 7x^{2} + 15.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 4.**

Find the approximate change in the volume V of a cube of side x metres caused by increasing the side by 1%.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 5.**

Find the approximate change in the surface area of a cube of side x metres caused by decreasing the side by 1%.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 6.**

If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the approximate error in calculating its volume.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 7.**

If the radius of a sphere is measured as 9 m with an error of 0.03 m, then find the approximate error in calculating its surface area.

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 8.**

If f(x) = 3x^{2} + 15x + 5, then the approximate value of f (3.02) is

(A) 47.66 (B) 57.66 (C) 67.66 (D) 77.66

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**NCERT Solutions for Class 12 Maths Application of Derivatives ****Exercise**** 6.4: Ques No 9.**

The approximate change in the volume of a cube of side x metres caused by increasing the side by 3% is (A) 0.06 x^{3} m^{3} (B) 0.6 x^{3} m^{3} (C) 0.09 x^{3} m^{3} (D) 0.9 x^{3} m^{3}

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