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CUET Physics Mock Test Wave Optics AMBIPi

Hi CUET aspirants, Welcome to Amans Maths Blogs (AMBIPi). In this post, you will get CUET Physics Mock Test Wave Optics AMBIPi. This CUET Physics Mock Test is of the Physics chapter Wave Optics. Before solving these CUET Physics questions, you must read CUET Physics Notes, which helps you to revise CUET Physics Syllabus and then you must need to solve CUET Previous Years Questions Papers.

CUET Physics Mock Test

CUET Physics Question No: 1

By corpuscular theory of light, the phenomenon which can be explained is

Option A : Refraction

Option B : Interference

Option C : Diffraction

Option D : Polarisation

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Option A: Refraction

Corpuscular theory explains refraction of light.

CUET Exam Physics Question No: 2

According to corpuscular theory of light, the different colours of light are due to

Option A : Different electromagnetic waves

Option B : Different force of attraction among the corpuscles

Option C : Different size of the corpuscles

Option D : None

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Option C: Different size of the corpuscles

According to corpuscular theory different colours of lights are due to different sizes of corpuscules.

CUET UG Physics Question No: 3

The idea of the quantum nature of light has emerged in an attempt to explain

Option A : Interference

Option B : Diffraction

Option C : Radiation spectrum of a black body

Option D : Polarisation

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Option C: Radiation spectrum of a black body

According t Planks hypothesis, black bodies emit radiations in the form of photons.

CUET Domain Subject Physics Question No: 4

By Huygen’s wave theory of light, we cannot explain the phenomenon of

Option A : Interference

Option B : Diffraction

Option C : Photoelectric effect

Option D : Polarisation

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Option C: Photoelectric effect

Huygen’s wave theory fails to explains the particles nature of light (i.e., photoelectric effect)

CUET BSc Physics Question No: 5

The idea of secondary wavelets for the propagation of a wave was first given by

Option A : Newton

Option B : Huygen

Option C : Maxwell

Option D : Fresnel

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Option B: Huygen 

The idea of secondary wavelets is given by Huygen. 

CUET Entrance Exam Physics Question No: 6

Which one of the following phenomenon is not explained by Huygen’s construction of wavefront

Option A : Refraction

Option B : Reflection

Option C : Diffraction

Option D : Origin of spectra

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Option D: Origin of spectra

Origin of spectra is not explained by Huygen’s theory.

CUET Exam Question No: 7

Two coherent sources of light can be obtained by

Option A : Two different lamps

Option B : Two different lamps but of the same power

Option C : Two different lamps of same power and having the same colour

Option D : None of these

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Option D: None of these

In non-uniform electric field. Intensity is more, where the lines are more denser.

CUET Physics Practice Questions No: 8

The phenomenon of interference is shown by

Option A : Longitudinal mechanical waves only

Option B : Transverse mechanical waves only

Option C : Electromagnetic waves only

Option D : All the above

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Option D: All the above

Interference is shown by electromagnetic as well as mechanical waves.

CUET Physics Sample Paper Question No: 9

Soap bubble appears coloured due to the phenomenon of

Option A : Interference

Option B : Diffraction

Option C : Dispersion

Option D : Reflection

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Option A: Interference

Phenomenon of interference of light takes place.

CUET Physics Mock Test Question No: 10

Wave nature of light is verified by

Option A : Interference

Option B : Photoelectric effect

Option C : Reflection

Option D : Refraction

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Option A: Interference 

Interference of light verifies the wave nature of light. 

CUET Physics Question No: 11

The frequency of light ray having the wavelength of 3800Å is

Option A :  9 × 1013 cycles/s

Option B : 1015 cycles/s

Option C : 90 cycles/s

Option D : 3000 cycles/s

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Option B: 1015 cycles/s   

v = c/λ = 3x 108  / 3000 x 10-8 = 1015 cycles/sec

CUET Exam Physics Question No: 12

A slit of width a is illuminated by white light. For red light ( = 6500 Å), the first minima is obtained at = 30°, then the value of a will be

Option A : 3250 Å 

Option B : 6.5 × 10–4 mm

Option C : 1.24 microns

Option D : 2.6 × 10–4 cm

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Option C: 1.24 microns

For first minima θ = λ/ a or a = λ/ θ 

.. a = 6500 x 10-8 x 6 / π ( As 30 = π/6 red)

= 1.24 x 10-4 cm = 1.24 microns

CUET UG Physics Question No: 13

The light of wavelength 6328 Å is incident on a slit of width 0.2 mm perpendicularly, the angular width of central maxima will be

Option A : 0.36°

Option B : 0.18°

Option C : 0.72° 

Option D : 0.09°

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Option A: 0.36°

The angular half width of the central maxima is given by sin θ = λ/a ⇒ θ = 6328 x 10-10x 180 / 0.2 x 10-3 rad  = 6382 x 10-10 x 180 / 0.2 x 10-3 x π degree = 0.18°

Total width of central maxima = 2 = 0.36°. 

CUET Domain Subject Physics Question No: 14

The penetration of light into the region of geometrical shadow is called

Option A : Polarisation

Option B : Interference

Option C : Diffraction

Option D : Refraction

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Option C: Diffraction

It is caused due to turning of light around corners

CUET BSc Physics Question No: 15

A diffraction is obtained by using a beam of red light. What will happen if the red light is replaced by blue light.

Option A : Bands will become narrower and crowd full together

Option B : Bands will become broader and further apart

Option C : No change will take place

Option D : Bands disappear

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Option A: Bands will become narrower and crowd full together

Band width α λ,  λblue<  λred,hence for blue light the diffraction bands becomes narrower and crowded together. 

CUET Entrance Exam Physics Question No: 16

Through which character we can distinguish the light waves from sound waves

Option A : Interference

Option B : Refraction

Option C : Polarisation

Option D : Reflection

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Option C: Polarisation

Polarisation is not shown by sound waves.

CUET Exam Question No: 17

The angle of polarisation for any medium is 60°, what will be critical angle for this

Option A : sin-1 √3

Option B : tan-1 √3

Option C : cos -1 √3

Option D : sin -1 1√3

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Option D: sin -1 1√3

By using μ = tan θp ⇒ μ = tan 60° = √3 also c = sin -1 (1/μ) ⇒ c = sin -1 (1 / √3)

CUET Physics Practice Questions No: 18

The angle of incidence at which reflected light is totally polarized for reflection from air to glass is

Option A : sin-1 (n)

Option B : sin -1 (1/n)

Option C : tan-1 (1/n)

Option D : tan-1 (n)

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Option D: tan-1 (n)

μn = tan θp ⇒ θp = tan-1 (n)

CUET Physics Sample Paper Question No: 19

Which of following cannot be polarised

Option A : Radio waves

Option B : Ultraviolet rays

Option C : Infrared rays

Option D : Ultrasonic waves

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Option D: Ultrasonic waves

Ultrasonic waves are longitudinal waves.

CUET Physics Mock Test Question No: 20

When an unpolarized light of intensity Io is incident on a polarizing sheet, the intensity of the light which does not get transmitted is

Option A : Zero

Option B :I

Option C : 1/2 Io

Option D : 1/4 Io

Show/Hide Answer Key

Option A: 1/4 Io

If an unpolarised light is converted into plane polarised light by passing through a polaroid, it’s intensity becomes half.

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