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JSTSE 2019-20 Question Paper With Answer Keys and Solutions

JSTSE 2019-20 Question Paper With Answer Keys Solutions

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JSTSE 2019-20 Question Paper With Answer Keys And Solutions

Hi students, welcome to AmansMathsBlogs (AMB). On this article, you will get JSTSE 2019-20 Question Paper With Answer Keys And Solutions.

JSTSE 2019-20 is an exam that is conducted by science branch of the Directorate of Education, Government of Delhi. In 2019-20 session, JSTSE is conducted on 15 December 2019 (Sunday). 

JSTSE 
Previous Year Question Papers
2007-08 2008-09 2009-10 2010-11 2011-12
2012-13 2013-14 2014-15 2015-16 2016-17
2018-19 Physics Chemistry Maths Biology

The math questions of JSTSE 2019-20 Question Paper are solved by me, AMAN RAJ, I am maths faculty of IIT Maths Foundation course and founder of this website AmansMathsBlogs (AMB).

Read More : 129 Maths Short Tricks

JSTSE 2019-20 Question Paper: PART – I (GK)

JSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys Solutions

JSTSE 2019-20 Question Paper: PART – II (GS & Maths)

JSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys SolutionsJSTSE 2019-20 Question Paper With Answer Keys Solutions

JSTSE 2019-20 Answer Keys: PART – I

General Knowledge JSTSE 2019-20 Answer Keys
Ques No Ans Key Ques No Ans Key Ques No Ans Key Ques No Ans Key
1 2 16 4 31 2 46 3
2 2 17 1 32 1 47 1
3 3 18 3 33 2 48 2
4 2 19 1 34 3 49 3
5 1 20 4 35 4 50 3
6 3 21 3 36 3
7 2 22 1 37 1
8 2 23 2 38 3
9 2 24 3 39 2
10 4 25 1 40 4
11 1 26 4 41 2
12 2 27 4 42 4
13 2 28 1 43 3
14 4 29 4 44 3
15 1 30 4 45 4

JSTSE 2019-20 Answer Keys: PART – II

General Science (51 to 170) & Mathematics (171 to 200) JSTSE 2019-20 Answer Keys
Ques No Ans Key Ques No Ans Key Ques No Ans Key Ques No Ans Key
51 2 91 3 131 4 171 1
52 4 92 2 132 1 172 1
53 2 93 3 133 4 173 3
54 1 94 1 134 2 174 Bonus
55 3 95 2 135 2 175 3
56 2 96 3 136 2 176 3
57 1 97 1 137 3 177 3
58 2 98 2 138 1 178 2
59 4 99 2 139 2 179 3
60 1 100 4 140 1 180 1
61 1 101 1 141 3 181 4
62 2 102 2 142 2 182 1
63 1 103 4 143 4 183 4
64 2 104 1 144 1 184 1
65 2 105 2 145 1 185 4
66 3 106 2 146 1 186 4
67 4 107 1 147 1 187 3
68 4 108 1 148 1 188 4
69 2 109 3 149 2 189 3
70 1 110 3 150 3 190 1
71 3 111 2 151 3 191 2
72 1 112 3 152 4 192 1
73 3 113 1 153 2 193 2
74 2 114 3 154 2 194 4
75 3 115 4 155 1 195 4
76 4 116 2 156 1 196 1
77 4 117 1 157 1 197 2
78 3 118 2 158 1 198 1
79 2 119 3 159 1 199 3
80 2 120 4 160 3 200 1
81 4 121 2 161 3
82 1 122 1 162 3
83 2 123 2 163 3
84 3 124 4 164 1
85 3 125 1 165 1
86 2 126 3 166 3
87 3 127 1 167 4
88 1 128 2 168 1
89 1 129 4 169 2
90 1 130 3 170 1

JSTSE 2019-20 Answer Keys With Solutions (Math)

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 171

If ((x+1)/(x+3))3 = (x-1)/(x+5), then the value of x is 

Options:

1. 2

2. -2

3. 1

4. -1

Answer Key: 2

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 172

The value of 1/(2 + √3 – 2√2) + 3/(2 + √3 + 2√2) is

Options:

1. (4/47)[9√3 – 4√6 – √2 + 14]

2. (4/47)[9√3 + 4√6 – √2 + 14]

3. (4/47)[9√3 – 4√6 – √2 – 14]

4. (4/47)[9√3 + 4√6 + √2 + 14]

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 173

If x = 5√21 / (√3 + √7), then the value of (x + 5√7)/(x – 5√7) – (x + 5√3)/(x – 5√3) is

Options:

1. 2

2. √21

3. 8/√21

4. 4/√21

Answer Key: 3

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 174

If the polynomials p(x) = 4x3 – ax2 + 2x – 1 and q(x) = 3x3 – 7x2 – 8x + a leave the same remainder, when divided by (x – 1), then the value of a is

Options:

1. 1

2. 1/2

3. 3/2

4. -3/2

Answer Key: Not in Options

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 175

Factors of 6x2 – 5xy – 4y2 + x + 17y – 15 is

Options:

1. (2x + y – 3)(3x – 4y + 5)

2. (2x – y – 3)(3x – 4y – 5)

3. (2x – y – 3)(3x + 4y + 5)

4. (2x + y + 3)(3x + 4y – 5)

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 176

If x = ∛28 and y = ∛27, then the value of (x + y) – 1/(x2 + xy + y2) is

Options:

1. 8

2. 7

3. 6

4. 5

Answer Key: Given question is wrong: Correct term is (x – y) – 1/(x2 + xy + y2).

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 177

The value of 0.2 + 0.23 is

Options:

1. 0.43

2. 0.43

3. 0.45

4. 0.45

Answer Key: 3

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 178

If x, y and z are real numbers, then (x – 2)2 + (y – 3)2 + (z – 4)2 = 0, then the value of xy + yz + zx is

Options:

1. 24

2. 26

3. 28

4. 30

Answer Key: 2

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 179

If p2 – 3p – 1 = 0, then the value of p2 + 1/p2 is

Options:

1. 7

2. 9

3. 11

4. 13

Answer Key: 3

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 180

If m + n = 7 and m3 + n3 = 133, then the value of (m2 + n2) is

Options:

1. 29

2. 49

3. 69

4. 59

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 181

If x + y = √3, x – y = √2, then the expression 8xy(x2 + y2) has the value

Options:

1. 5√2

2. 10√2

3. 20

4. 5

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 182

Factors of (3×2 – 2x)(6 – 3×2 +2x) – 5 are

Options:

1. (x – 1)(x + 1)(1 + 3x)(5 – 3x)

2. (x – 1)(x + 1)(1 + 3x)(5 + 3x)

3. (x – 1)(x + 1)(1 – 3x)(3 + 5x)

4. (x – 1)(x + 1)(3 – x)(5 – 3x)

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 183

If m = 2p + √(p2 + k), then the value of k in terms of p and m is

Options:

1. (m + p)(m + 3p)

2. (m + p)(m – 3p)

3. (m – 2p)(m – 3p)

4. (m – p)(m – 3p)

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 184

If p – x = 1 and (3x + 2)/5 + 3/2 = (4p – 3)/2, then the value of x is

Options:

1. 1

2. -1

3. 0

4. 2

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 185

If 52m-1 = 25n-1 + 100, then the value of 6-m is

Options:

1. 6

2. 36

3. 1/6

4. 1/36

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 186

If x = 3 + 31/3 + 32/3, then the value of x3 – 9x2 + 18x – 10 is

Options:

1. -1

2. 0

3. 1

4. 2

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 187

If a + b + c = 2, ab + bc + ca = -1 and abc = -2, then the value of a3 + b3 + c3 is

Options:

1. -8

2. 0

3. 8

4. 16

Answer Key: 3

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 188

The coefficient of x2 in (x+3)(x-5)(x+7) is

Options:

1. 28

2. -28

3. -5

4. 5

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solution: Ques No 189

In the figure, AD = AC = CB, then the value of x is

Options:

1. 51 degree

2. 78 degree

3. 34 degree

4. 43 degree

Answer Key: 3

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 190

If (√32)m / 2n+1 = 1 and 164-m/2 – 8n = 0, then the value of m and n are

Options:

1. m = 2 and n = 4

2. m = 2 and n = 3

3. m = 4 and n = 2

4. m = 3 and n = 2

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 191

In the figure, O is the center of the circle, angle OAB = 32 degree and angle APD = 90 degree then the value of x is

Options:

1. 30 degree

2. 32 degree

3. 34 degree

4. 36 degree

Answer Key: 2

Solution:

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 192

In the figure, O is the center of the circle, angle QRO = 30 degree, then the values of a and b are

Options:

1. a = 30 degree and b = 30 degree

2. a = 15 degree and b = 15 degree

3. a = 15 degree and b = 30 degree

4. a = 30 degree and b = 15 degree

Answer Key: 2

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 193

If the volume of a cube is L cubic units, its surface area is M square units and length of the diagonals is N units, then

Options:

1. 6L = MN

2. 6√3L = MN

3. √3M = LN

4. 6N = LM

Answer Key: 2

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 194

In a triangle, the average of any two sides is 6 cm more than half of third side, then the area of the triangle is 

Options:

1. 64√3

2. 48√3

3. 72√3

4. 36√3

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 195

The area of circular ring enclosed between two concentric circles is 286 cm2. If the difference of their radii is 7 cm, then the radii of these circles are

Options:

1. 2 cm and 9 cm

2. 5 cm and 12 cm

3. 4 cm and 11 cm

4. 3 cm and 10 cm

Answer Key: 4

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 196

If 49x – 49x-1 = 16464, then which of the following is equivalent of (2x)x?

Options:

1. (5)5/2

2. (7)7/2

3. (3)3/2

4. None of these

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 197

The ratio of the volumes of a cube to that of a sphere which will fit in side the sphere is 

Options:

1. √3π : 2

2. 2 : √3π 

3. 3 : √2π

4. None of these

Answer Key: 2

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 198

The value of ∛(20 + 14√2) + ∛(20 – 14√2) is

Options:

1. 4

2. 6

3. 8

4. 10

Answer Key: 1

Solution:

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 199

If m + 1/m = 5, then the value of (m4 + 3m3 + 5m2 + 3m + 1)/(m4 + 1) is

Options:

1. 47/21

2. 45/21

3. 43/23

4. 41/23

Answer Key: 3

Solution:

JSTSE 2019-20 Question Paper With Answer Keys and Solutions: Ques No 200

If x : y : z = 4 : 3 : 2 and x2 + y2 + z2 = 11600, then the value of √(x + y – z) is

Options:

1. 10

2. 100

3. 180

4. 60

Answer Key: 1

Solution:

JSTSE-2019-20-Question-Paper-With-Answer-Keys-Solutions

JSTSE 
Previous Year Question Papers
2007-08 2008-09 2009-10 2010-11 2011-12
2012-13 2013-14 2014-15 2015-16 2016-17
2018-19 Physics Chemistry Maths Biology

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JSTSE 2019-20 Question Paper With Answer Keys and Solutions

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