JSTSE 2018-19 Question Paper With Answer Keys And Solutions

Hi students, welcome to AmansMathsBlogs (AMB). On this article, you will get JSTSE 2018-19 Question Paper With Answer Keys And Solutions.

JSTSE 2018-19 is an exam that is conducted by science branch of the Directorate of Education, Government of Delhi. In 2018-19 session, JSTSE is conducted on 20 January 2019 (Sunday). 

JSTSE
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The math questions of JSTSE 2018-19 Question Paper are solved by me, AMAN RAJ, I am maths faculty of IIT Maths Foundation course and founder of this website AmansMathsBlogs (AMB).

Read More : 129 Maths Short Tricks

JSTSE 2018-19 Question Paper: PART – I (GK)

JSTSE 2018-19 Question Paper: PART – II (GS & Maths)

JSTSE 2018-19 Answer Keys: PART – I

General Knowledge JSTSE 2018-19 Answer Keys
Ques No	Ans Key	Ques No	Ans Key	Ques No	Ans Key	Ques No	Ans Key
1	1	16	3	31	4	46	2
2	4	17	4	32	3	47	4
3	3	18	3	33	1	48	4
4	1	19	4	34	1	49	2
5	1	20	1	35	2	50	4
6	3	21	2	36	4
7	4	22	2	37	2
8	2	23	3	38	2
9	1	24	2	39	2
10	1	25	2	40	2
11	1	26	1	41	3
12	2	27	2	42	4
13	4	28	1	43	3
14	1	29	4	44	3
15	3	30	1	45	4

JSTSE 2018-19 Answer Keys: PART – II

General Science (51 to 170) & Mathematics (171 to 200) JSTSE 2018-19 Answer Keys
Ques No	Ans Key	Ques No	Ans Key	Ques No	Ans Key	Ques No	Ans Key
51	1	91	2	131	3	171	2
52	4	92	1	132	1	172	3
53	1	93	4	133	2	173	4
54	2	94	1	134	2	174	2
55	2	95	2	135	1	175	3
56	2	96	2	136	1	176	3
57	2	97	1	137	3	177	1
58	1	98	4	138	2	178	2
59	1	99	2	139	1	179	1
60	1	100	2	140	2	180	2
61	2	101	4	141	4	181	1
62	3	102	4	142	3	182	2
63	2	103	3	143	4	183	4
64	1	104	3	144	2	184	4
65	3	105	1	145	3	185	2
66	2	106	1	146	2	186	4
67	3	107	4	147	2	187	4
68	2	108	3	148	3	188	1
69	3	109	3	149	4	189	1
70	2	110	3	150	2	190	3
71	3	111	2	151	1	191	2
72	1, 2	112	3	152	1	192	3
73	2	113	2	153	3	193	1
74	2	114	4	154	1	194	4
75	4	115	1	155	4	195	3
76	3	116	2	156	4	196	2
77	2	117	4	157	2	197	2
78	2	118	2	158	1	198	3
79	3	119	4	159	3	199	2
80	3	120	1	160	4	200	3
81	4	121	3	161	2
82	2	122	2	162	1
83	2	123	4	163	3
84	2	124	2	164	4
85	4	125	1	165	3
86	3	126	3	166	4
87	2	127	3	167	1
88	1	128	1	168	2
89	3	129	3	169	2
90	1	130	4	170	3

JSTSE 2018-19 Answer Keys With Solutions (Math)

JSTSE 2018-19 Question Paper With Solutions: Ques No 171

If x = , then the value of x² + (39/x)² is 

Options:

A. 104

B. 114

C. 124

D. 144

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 172

If a/b + b/a = 1, (a, b  0) then the value of a³ + b³ is 

Options:

A. 1

B. -1

C. 0

D. 2

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 173

If value of  is

Options:

A. 8(3)^(1/2)

B. 2(3)^(1/2)

C. 3(2)^(1/2)

D. (6)^(1/2)

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 174

If one angle of a triangle is 130, then the angle between the angle bisectors of the other two angles is

Options:

A. 145 degree

B. 155 degree

C. 135 degree

D. 95 degree

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 175

If 4^x – 4^x-1 = 24, then (2x)^x equals 

Options:

A. 5Root(5)

B. Root(5)

C. 25Root(5)

D. 125

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 176

If [(2.3)³ – (0.027)]/[(2.3)² + 0.69 + 0.09] = k, then the value of k is

Options:

A. 2.273

B. 2.327

C. 2

D. 3

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 177

If (3x – 1)⁷ = a₇x⁷ + a₆x⁶ + a₅x⁵ + … + a₁x + a₀, then the value of (a₇ + a₆ + a₅ + a₄ + a₃ + a₂ + a₁ + a₀) is

Options:

A. 128

B. 64

C. 0

D. 32

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 178

If a : b = 2 : 3, x : y = 3 : 4, then the value of (25by – 2ax)/(3ay + 4bx) is

Options:

A. 5 : 24

B. 24 : 5

C. 1 : 2

D. 2 : 1

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 179

If x³ – 3x² + 3x + 7 = (x + 1)(ax² + bx + c), then the value of (a + b + c) is

Options:

A. 4

B. 12

C. -10

D. 3

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 180

In the given figure (see QNo: 180 in above question paper), PQRS is a square. RST is an equilateral triangle, then the value of x is.

Options:

A. 60 degree

B. 75 degree

C. 45 degree

D. 80 degree

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 181

One angle of a pentagon is 140 degree. If the remaining angles are in the ratio of 1:2:3:4, then the greatest angle is

Options:

A. 160 degree

B. 170 degree

C. 140 degree

D. 150 degree

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 182

If the mean of age of 18 students of a class is 14.5 years, two more students of ages 15 years and 16 years join the class, then the new mean of age is

Options:

A. 14 years

B. 14.6 years

C. 14.5 years

D. 14.7 years

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 183

The value of  is 

Options:

A. 9

B. 8

C. 6

D. 7

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 184

In the given triangle RST (see QNo: 184 in above question paper), the value of x is 

Options:

A. 40 degree

B. 90 degree

C. 80 degree

D. 100 degree

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 185

If the cost price of 25 articles is equal to the selling price of 20 article, the gain percentage is

Options:

A. 20%

B. 25%

C. 5%

D. 10%

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 186

The value of 

is

Options:

A. 3/22

B. 41/100

C. 1/2

D. 9/22

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 187

If a = 2 + Root(3), then the value of (a – 1/a) is

Options:

A. 0

B. 2 + Root(3)

C. 4

D. 2Root(3)

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 188

In the given figure (see QNo: 188 in above question paper), AB || HG, then the value of a is

Options:

A. 8

B. 9

C. 7.5

D. 10

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 189

If one factor of (x⁴ + x² – 20) is (x² + 5). The other factor is

Options:

A. x² – 4

B. x² + 4

C. x – 4

D. x + 20

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 190

If x = 7 + 4Root(3) and xy = 1, then (1/x² + 1/y²) is

Options:

A. 64

B. 134

C. 194

D. 149

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solutions: Ques No 191

If 5^2m-1 = 25^m-1 + 100, then the value of 3^2+m is

Options:

A. 27

B. 81

C. 9

D. 343

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 192

If 5 coins are tossed together, what will be the probability of getting at least two heads?

Options:

A. 1/32

B. 3/16

C. 13/16

D. 5/16

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 193

If , then the value of (x – y) is

Options:

A. 16

B. 38

C. 22

D. 21

Answer Key: A

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 194

If p + q + r = 0, then the value of (q + r)²/qr + (r + p)²/rp + (p + q)²/pq is

Options:

A. 0

B. 1

C. 2

D. 3

Answer Key: D

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 195

If 2l – m + n = 0, then the value of 4l² – m² + n² + 4ln is 

Options:

A. 1

B. -1

C. 0

D. 2

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 196

If m² + 1/25m² = 43/5, then the value of m³ + 1/125m³ is

Options:

A. 50(1/5)

B. 25(1/5)

C. 12(1/5)

D. 15(1/5)

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 197

The cost price of a bag and a book is Rs. 371. If the bag costs 12% more than the book, then the cost price of the bag is

Options:

A. Rs. 175

B. Rs. 196

C. Rs. 150

D. Rs. 221

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 198

In the given figure (see QNo: 198 in above question paper), AE = DC = 13 cm, BE = 5 cm, angle ABC = 90 degree and AD = EC, then the length of AD is

Options:

A. 5 cm

B. 6 cm

C. 7 cm

D. 12 cm

Answer Key: C

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 199

Two dice are rolled, then the probability of getting a total of 9 is

Options:

A. 1/3

B. 1/9

C. 9/10

D. 8/9

Answer Key: B

Solution:

JSTSE 2018-19 Question Paper With Solution: Ques No 200

If A:B:C = 2:3:4 and A² + B² + C² = 11600, then the value of (A + B + C) is

Options:

A. 20

B. 24

C. 60

D. 100

Answer Key: C

Solution:

JSTSE
Previous Year Question Papers
2007-08	2008-09	2009-10	2010-11	2011-12
2012-13	2013-14	2014-15	2015-16	2016-17
2018-19	Physics	Chemistry	Maths	Biology

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